The mid point of ab is m(-2,-6) if the coordinates of a are (-1,4) what are the coordinates of B

One number exceeds another by 5 the sum of the numbers is 37 . What are the numbers

Eduardwww [97]

One number = x
Another number = y

x = y + 5
x + y = 37

(y + 5) + y = 37
2y + 5 = 37
2y = 32
y = 16

x = (16) + 5
x = 21

The numbers are 16 and 21.

5 0

3 years ago

The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the

Degger [83]

Using the normal distribution, we have that:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, the parameters are given as follows:

$\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358$

Hence:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{58 - 57}{22}$

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 57}{22}$

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

$Z = \frac{X - \mu}{s}$

$Z = \frac{58 - 57}{5.3358}$

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

$Z = \frac{X - \mu}{s}$

$Z = \frac{55 - 57}{5.3358}$

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0

2 years ago

What is the median of the data displayed in this box-and-whisker plot? A.41 B.49 C.55 D.58

lutik1710 [3]

The median in a whisker plot is the dot or line in the box on the line. In this case, the dot is at 41, so the median is 41.

ANSWER: A) 41 is the median

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

I need help with Question 14 . I need to submit it by monday...<br> Pls help

GaryK [48]

Answer:

Distance between A and B is 5400 meters

Step-by-step explanation:

Consider "D" the letter to identify distance between A and B

Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:

Recall that distance equals the speed times the time:

distance= speed * time

First encounter:

100 * t = D - 80 * t

180 * t = D Equation (1)

Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .

Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:

100 *(t+6) = D - 75 * (t+6)

100 t + 600 = D - 75 t - 450

175 T + 150 = D Equation (2)

Now, let's equal equation (1) to equation (2), since D should be the same:

180 t = 175 t + 150

5 t = 150

t = 30

Then the time t (first encounter) is 30 minutes. Knowing this, we can use either equation to find D:

From Equation (1) for example: D = 180 * t = 180 * 30 = 5400 meters

5 0

4 years ago

Myles is working on his typing. He types for 3 minutes straight and is able to type 150 words. Determine how long it would take

erastova [34]

I think the answer is 6 because 900/150= 6 and 6X150 is 900 :)

6 0

3 years ago