How much power can I generate while lifting a mass for 30 seconds?

A tennis ball is dropped from 1.43 m above the

Rudiy27

Answer:

-5.29 m/s

Explanation:

Given:

y₀ = 1.43 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)

v = -5.29 m/s

4 0

4 years ago

The potential difference between two points is 14.9 V when a 0.0400 C charge moves between these points by how much does its pot

ad-work [718]

Answer:

The potential energy change is 0.596 J.

Explanation:

Given that,

Potential difference =14.9 V

Charge q =0.0400 C

We need to calculate the change potential energy

The potential energy change is the product of the charge and potential difference.

Using formula of change potential energy

$\Delta U=q\Delta V$

$\Delta U=0.0400\times14.9$

$\Delta U=0.596\ J$

Hence, The potential energy change is 0.596 J.

7 0

3 years ago

) Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. the electric field at a point P, whic

aleksandr82 [10.1K]

Answer:

Explanation:

Point P is situated outside sphere . For a non conducting sphere , electric field outside sphere is given by the relation

E = k Q / d²

15000 = 9 x 10⁹ x Q / .5²

Q = 416.67 X 10⁻⁹

Maximum field will be when d = r ( radius )

maximum E = kQ / r²

= 9 x 10⁹ x 416.67 X 10⁻⁹ / .3²

= 41667 N / C

8 0

3 years ago

Suppose there is a pendulum with length 5m hanging from a ceiling. A ball of mass 2kg is attached is attached to the bottom of t

Dafna1 [17]

Answer:

1.84 m from the initial point (3.16 m from the ceiling)

Explanation:

According to the law of conservation of energy, the initial kinetic energy of the ball will be converted into gravitational potential energy at the point of maximum height.

Therefore, we can write:

$\frac{1}{2}mv^2 = mg\Delta h$

where

m = 2 kg is the mass of the ball

v = 6 m/s is the initial speed of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

$\Delta h$ is the change in height of the ball

Solving for $\Delta h$ ,

$\Delta h = \frac{v^2}{2g}=\frac{6^2}{2(9.8)}=1.84 m$

So, the ball raises 1.84 compared to its initial height.

Therefore:

- if we take the initial position of the ball as reference point, its maximum height is at 1.84 m

- if we take the ceiling as reference point, the maximum height of the ball will be

5 m - 1.84 m = 3.16 m from the ceiling

7 0

4 years ago

Elements that cycle in the environment and that also have a gaseous phase at some point in their cycle include what?

Bingel [31]

Answer:

Carbon, nitrogen and sulphur.

Explanation:

In carbon cycle, carbon dioxide is in the gaseous form in atmosphere. This gaseous carbon dioxide is emitted in the atmosphere through combustion of fossils, respiration, decomposition. In nitrogen cycle, atmospheric nitrogen is in the gaseous form which is emitted through denitrification. In sulphur cycle, sulphur is in the form of gaseous sulphur dioxide in the atmosphere. This sulphur is emitted in the atmosphere by the volatilization of hydrogen sulphide.

7 0

4 years ago