Answer:
Okay you have isolate a variable. As long as you perform the some operation on both sides the equations holds true. So I'll multiply the bottom one by three. 3x - 3y = 27. Now if I add the equations together I get 5x is 35 or x is 7. Then plug it back into either equation. 7 minus what is 9? -2. Y is -2
Answer:
![a_{10} = \frac{10}{65536}](https://tex.z-dn.net/?f=a_%7B10%7D%20%3D%20%5Cfrac%7B10%7D%7B65536%7D)
Step-by-step explanation:
The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.
This sequence is arithmetic if:
![a_{3} - a_{2} = a_{2} - a_{1}](https://tex.z-dn.net/?f=a_%7B3%7D%20-%20a_%7B2%7D%20%3D%20a_%7B2%7D%20-%20a_%7B1%7D)
We have that:
![a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}](https://tex.z-dn.net/?f=a_%7B3%7D%20%3D%2040%2C%20a_%7B2%7D%20%3D%2010%2C%20a_%7B3%7D%20%3D%20%5Cfrac%7B5%7D%7B2%7D)
![a_{3} - a_{2} = a_{2} - a_{1}](https://tex.z-dn.net/?f=a_%7B3%7D%20-%20a_%7B2%7D%20%3D%20a_%7B2%7D%20-%20a_%7B1%7D)
![\frac{5}{2} - 10 = 10 - 40](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20-%2010%20%3D%2010%20-%2040)
![\frac{-15}{2} \neq -30](https://tex.z-dn.net/?f=%5Cfrac%7B-15%7D%7B2%7D%20%5Cneq%20-30)
This is not an arithmetic sequence.
This sequence is geometric if:
![\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}](https://tex.z-dn.net/?f=%5Cfrac%7Ba_%7B3%7D%7D%7Ba_%7B2%7D%7D%20%3D%20%5Cfrac%7Ba_%7B2%7D%7D%7Ba_%7B1%7D%7D)
![\frac{\frac{5}[2}}{10} = \frac{10}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B5%7D%5B2%7D%7D%7B10%7D%20%3D%20%5Cfrac%7B10%7D%7B40%7D)
![\frac{5}{20} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B20%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
![\frac{1}{4} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
This is a geometric sequence, in which:
The first term is 40, so ![a_{1} = 40](https://tex.z-dn.net/?f=a_%7B1%7D%20%3D%2040)
The common ratio is
, so
.
We have that:
![a_{n} = a_{1}*r^{n-1}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20a_%7B1%7D%2Ar%5E%7Bn-1%7D)
The 10th term is
. So:
![a_{10} = a_{1}*r^{9}](https://tex.z-dn.net/?f=a_%7B10%7D%20%3D%20a_%7B1%7D%2Ar%5E%7B9%7D)
![a_{10} = 40*(\frac{1}{4})^{9}](https://tex.z-dn.net/?f=a_%7B10%7D%20%3D%2040%2A%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7B9%7D)
![a_{10} = \frac{40}{262144}](https://tex.z-dn.net/?f=a_%7B10%7D%20%3D%20%5Cfrac%7B40%7D%7B262144%7D)
Simplifying by 4, we have:
![a_{10} = \frac{10}{65536}](https://tex.z-dn.net/?f=a_%7B10%7D%20%3D%20%5Cfrac%7B10%7D%7B65536%7D)
The unknown number is - 2.5
Let the number = n
The equation will be formed as follows;
- eight times a number plus two = 8n + 2
- Two times the quantity of eight times a number plus two = 2(8n + 2)
- two times the same number minus seven = 2n - 7
- three the quantity of two times the same number minus seven = 3(2n-7)
Our final equation becomes;
2(8n + 2) = 3(2n-7)
Simplify as follow, to determine the unknown number;
16n + 4 = 6n - 21
16n - 6n = -25
10n = -25
n = -2.5
Thus, the unknown number is - 2.5
Learn more here: brainly.com/question/13818690
Answer 1 = I believe you are correct cause when doing area , remembering you times the different area of the sides
Answer 2 = I believe the answer is C (2,0009) cause remember adding when doing volume but there are few steps ..
. i have done the work for this and hoping my work helped the answer i got help you! comment below if you need anything , thanks , have a nice day!!
Because A Rectangle is not a Cube?