Question

Which launch angle would give you a largest height in projectile motion?

Answer 1

Answer:

45degres

Explanation:

A projectile travels the farthest when it is launched at an angle of 45 degrees.

Answer 2

Answer:

90 degrees

Explanation:

Using the equation D=$\frac{Vf+VI}{2}*t$, the final velocity is 0 m/s at its highest point, and its initial velocity is Vi*sin(theta). Plugging this in, you will get $\frac{Vi*Sin(theta)}{2} *t=D$. In this case, to get the largest value of D, you want sin(theta) to be its largest value. We can do this by changing the angle. Sin(theta) is at its largest value of 1 when you plug in sin(90). As a result, the angle which would result in the largest height would be 90 degrees.