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Alisiya [41]
3 years ago
7

The train slows down at the railroad crossing. Is that acceleration, velocity, speed, of none of the above?​

Physics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

none of the above

Explanation:

im pretty positive this is the answer tell me if i am wrong please

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LVULAN
3241004551 [841]

For this case we have that by definition, the kinetic energy is given by the following formula:

k= \frac {1} {2} * m * v ^ 2

Where:

m: It is the mass

v: It is the velocity

According to the data we have to:

m = 100 \ kg\\v = 9 \frac {m} {s}

Substituting the values we have:

k = \frac {1} {2} * (100) * (9) ^ 2\\k = \frac {1} {2} * (100) * 81\\k = 50 * 81\\k = 4050

finally, the kinetic energy is 4050 \ J

Answer:

Option A

7 0
3 years ago
A light, rigid rod is 55.8 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at res
VMariaS [17]

To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have

KE = PE

\frac{1}{2} mv^2 = mgh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(2(55.8*10^{-2}))}

v = 4.67m/s

Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s

4 0
3 years ago
What law states that, in any process, energy is neither created nor destroyed?
kupik [55]
The law<span> of conservation of </span><span>energy.</span>
8 0
3 years ago
A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If of work are done by the strap while moving the sui
ollegr [7]

Answer:

The tension in the strap is 74.82 N.

Explanation:

Given that,

Angle between the horizontal and the suitcase is 36 degrees.

The distance traveled by the suitcase is 15 meters.

Let the work done by the suitcase is 908 J. We know that the work done in the vector form is given by :

W=Fd\ \cos\theta\\\\908=F\times 15\times cos(36)\\\\F=74.82\ N

So, the tension in the strap is 74.82 N. Hence, this is the required solution.

6 0
3 years ago
The pull is always toward the _____ of the planet
Nataly [62]
The correct answer is center. Hope this helps.
8 0
3 years ago
Read 2 more answers
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