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2 years ago

How many grams of Lioh are in 1.7 moles please help

Chemistry

2 answers:

stepan [7]2 years ago

7 0

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles LiOH, or 23.94834 grams.

natali 33 [55]2 years ago

4 0

Answer:

23.94834 gram

Explanation:

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What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

ArbitrLikvidat [17]

Data:

m (Sample Mass) = ?
n (Number of moles) = 0.714 mol
MM (Molar Mass) of Mercury (I) Chloride ( $Hg_{2} Cl_{2}$ )
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass $Hg_{2} Cl_{2}$ = 401.18 + 70.906 = 472.086 ≈ 472.09 amu or 472.09 g/mol

Formula:

$n = \frac{m}{MM}$

Solving:

$n = \frac{m}{MM}$
$0.714 = \frac{m}{472.09}$
$m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark$

Answer:
By approximation would be letter D) 337.2 g

8 0

3 years ago

What is the partial pressure of helium gas in a mixture that contains 8.00 grams of helium and 8.60 mol argon gas with a total p

Agata [3.3K]

Answer:

$P_{He}=9.06torr$

Explanation:

Hello there!

In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:

$P_{He}=x_{He}P_T$

Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:

$n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189$

Then, we calculate the partial pressure as shown below:

$P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr$

Best regards!

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3 years ago

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Westkost [7]

Answer:

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Explanation:

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Answer:it’s C

Explanation:

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2 years ago

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