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sukhopar [10]
3 years ago
7

A mother has four times the mass of her young son. Both are running with the same kinetic energy. Part A What is the ratio vs/vm

other of their speeds
Physics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer: 2:1

Explanation:

Given

Mother has four times the mass of young son

If they possess same kinetic energy then K_m=K_s

\Rightarrow K_m=\dfrac{1}{2}\times m_m\times v^2_m

\Rightarrow K_s=\dfrac{1}{2}\times m_s\times v^2_s

Equate the energy

\Rightarrow \dfrac{1}{2}\times m_m\times v^2_m=\dfrac{1}{2}\times m_s\times v^2_s\\\\\Rightarrow \dfrac{1}{2}\times 4m_s\times v^2_m=\dfrac{1}{2}\times m_s\times v^2_s\\\\\Rightarrow 4 v^2_m=v^2_s\\\\\Rightarrow \dfrac{v_s}{v_m}=\sqrt{4}\\\\\Rightarrow \dfrac{v_s}{v_m}=2

Thus, the ratio of speed is 2:1.

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Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to
andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3   ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = \frac{m1v}{3v3}  -----  ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 =  2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0
3 years ago
True or False. Alfred Wegener contributed greatly to the theory of plate tectonics by collecting and analyzing fossil, glacial a
bearhunter [10]

Answer:

The Answer would be True

Explanation:

8 0
2 years ago
Read 2 more answers
If the 0.09-mm-diameter tungsten filament in a light bulb is to have a resistance of 0.11 Ω at 20∘C, how long should it be?
skad [1K]

Answer:

Length L=0.0125 m

Explanation:

Given data

Resistance R=0.11Ω

Temperature T=20°C

Resistivity of tungsten at 20°C p=5.6×10⁻⁸Ω.m²

Radius of filament r=0.09/2 =0.045 mm =0.045×10⁻³m

To find

Length of filament L

Solution

The Cross section of area of filament is given as:

A=\pi r^{2}\\ A=\pi (0.045*10^{-3})^{2}\\A=6.3585*10^{-9}m^{2}

The Resistance of a material is given as:

R=p\frac{L}{A} \\L=\frac{AR}{p}\\ L=\frac{(6.3585*10^{-9})(0.11)}{5.6*10^{-8}}\\L=0.125m

6 0
3 years ago
A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th
Vesna [10]

Answer:

Average speed of car will be 48 km/hr  

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance t_1=\frac{d}{40}hr

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance t_2=\frac{d}{60}hr

So total time to cover 2d distance t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}

Average speed is the ratio of total distance to total time

So average speed =\frac{2d}{\frac{5d}{120}}=48km/hr

So average speed of car will be 48 km/hr

4 0
3 years ago
A race car is one lap behind the lead race car when the lead car has 55 laps to go in a race. If the speed of the lead car is 62
ella [17]

Answer:

The second car must go with a speed of 63.43 m/sec

Explanation:

Speed V of lead car = 62.3 m/sec

Distance S =   55 laps = 55 ×400 meters=22000 m

We know

S = V × t

So,

t= S/V

We put values of S and V here, we get

t=22000/62.3

t= 353.1 sec

So in 353.1 sec the second car which is one lap behind - must go a distance of 55+1=56 laps or 56×400 m = 22400 meters to catch the lead car before it finishes.

i-e for second car

Distance S= 22400m

Time t = 353.1 sec

V= ?

using again

S=Vt

we get

V= S/t

V= 22400/353.1= 63.43 m/sec

7 0
4 years ago
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