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tino4ka555 [31]

3 years ago

11

Hii please help i’ll give brainliest if you give a correct answer please

2 answers:

gavmur [86]3 years ago

4 0

Answer:

your body is exerting a force on the chair and nothing is happening

Explanation:

arsen [322]3 years ago

4 0

Answer:

the second one

Explanation:

as you sit down you are using gravitational force which is pulling straight down but as you sit down there are currently no forces in motion while sitting

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A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part

Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

$(I_p)s = \frac{\pi(0.55)4}2$

= 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

$T_{max} = T_{allow} \frac{I_p}{r}$

= $(14 \times 10^3) \times (\frac{0.14374}{0.55})$

= 3658.836 lb.in

= $\frac{3658.836}{12}$ lb.ft

= 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

$T_{max} = T_{allow}( \frac{Ip}{r})$

= $(14 \times10^3) \times ( \frac{0.13101}{0.55})$

= 3334.8 lb.in

= $(\frac{3334.8}{12} )$ lb.ft

= 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

$P_{max} = 2 \pi f_T$

= $2\pi(2.1) \times 304.9$

= 4023.061 lb. ft/s

= $(\frac{4023.061}{550})$ hp

= 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

$P _{max,t} = 2\pi f_T$

= $2\pi(2.1) \times 277.9$

= 3666.804 lb.ft /s

= $(\frac{3666.804}{550})$ hp

= 6.667 hp

7 0

3 years ago

Which best describes the convection currents in Earth’s mantle?

jonny [76]

<span>The Convection Currents are thought to play a part in the movement of the crustal plates on the earth.</span>

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A gun is fired vertically into a 1.40 kg block of wood at rest directly above it. If the bullet has a mass of 21.0 g and a speed

ahrayia [7]

To solve this problem we will use the theorems related to the conservation of momentum to determine the final speed of the system, once the bullet hits it. From there, we will calculate with the kinematic equations of linear motion, the height traveled with that speed. The conservation of momentum say us that,

$m_1u_1+m_2u_2 = (m_1+m_2)v_f$

Where,

$m_1 =$ mass of bullet

$m_2 =$ mass of block of wood

$u_{1,2} =$ Initital velocity of bullet and block of wood respectively.

$v_f =$ Final velocity

Our values are given as,

$m_1 = 1.40 Kg\\m_2 = 0.021 Kg\\u = 210 m/s$

Replacing we have that

$(1.40 + 0.021) * v_f = 0.021 * 210$

$v_f = 3.103 m/s$

Note that the initial velocity of wood block is 0 because is at rest

Now using the kinematic equation of motion we have that

$v_f^2-v_i^2 = 2gh$

As $v_i = 0$

$h = \frac{v_f^2}{2g}$

$h = \frac{3.103^2}{2 * 9.8}$

$h = 0.49 m$

Therefore the height reached by block after bullet embedding in it is 0.49 m

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4 years ago

What is the world record top speed for a NASCAR race car?

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