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2 years ago

Vitamin D has a percent composition of 42.98% C, and 57.02% H. Its molecular

Chemistry

1 answer:

Alex73 [517]2 years ago

3 0

Answer:

Dont use alot of points

Explanation:

people scam like me and ay the wrong answer and get the points :|

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An object has a mass of 2800g and a volume of 3cm3. What is its density?<br>

jeka57 [31]

Answer:

933.33 g/cm³

Explanation:

Density = mass / volume

Density = 2800/3 = 933.3 g/cm³.

4 0

2 years ago

What is the change in the freezing point of water when 35.0 g of sucrose is

frez [133]

From the calculations, we can see that, the change in the freezing point is -0.634°C.

<h3>What is freezing point?</h3>

The term freezing point refers to the temperature at which a liquid is changed to solid.

Given that;

ΔT = K m i

Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles

molality = 0.1 moles/ 300.0 * 10^-3 Kg

= 0.33 m

Thus;

ΔT = -1.86°C/mol * 0.33 m * 1

= -0.634°C

Learn more about freezing point:brainly.com/question/3121416

#SPJ1

3 0

1 year ago

Which of the following best represents potential energy being converted to kinetic energy? (2 points) The chemical energy in a b

Ilia_Sergeevich [38]

Answer: A woman kicks a soccer ball and scores a goal.

Explanation:

Potential energy: it is the energy possessed by the body due to its position.

Kinetic energy: it is the energy possessed by the the body due to its motion.

When a woman kick's a soccer ball she transferred her potential energy to soccer ball.Due to this action soccer ball comes into motion which means potential energy imparted to the ball starts getting converted into kinetic energy.

3 0

3 years ago

Read 2 more answers

What happens when chlorine from<br> CFCs mixes with ozone?

Svetach [21]

Answer:

Because they are extremely stable molecules, CFCs do not react easily with other chemicals in the lower atmosphere. ... Free chlorine atoms then react with ozone molecules, taking one oxygen atom to form chlorine monoxide and leaving an ordinary oxygen molecule.

Explanation:

5 0

2 years ago

II. Ionic Equations

mario62 [17]

Answer:

Complete ionic: $\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Net ionic: $\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

Explanation:

Start by identifying species that exist as ions. In general, such species include:

Soluble salts.
Strong acids and strong bases.

All four species in this particular question are salts. However, only three of them are generally soluble in water: $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ . These three salts will exist as ions:

Each $\rm AgNO_3\, (aq)$ formula unit will exist as one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion.
Each $\rm CaCl_2$ formula unit will exist as one $\rm Ca^{2+}$ ion and two $\rm Cl^{-}$ ions (note the subscript in the formula $\rm CaCl_2\!$ .)
Each $\rm Ca(NO_3)_2$ formula unit will exist as one $\rm Ca^{2+}$ and two $\rm {NO_3}^{-}$ ions.

On the other hand, $\rm AgCl$ is generally insoluble in water. This salt will not form ions.

Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ (three soluble salts) as the corresponding ions.

Pay attention to the coefficient of each species. For example, indeed each $\rm AgNO_3\, (aq)$ formula unit will exist as only one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion. However, because the coefficient of $\rm AgNO_3\, (aq)\!$ in the original equation is two, $\!\rm AgNO_3\, (aq)$ alone should correspond to two $\rm Ag^{+}\!$ ions and two $\rm {NO_3}^{-}\!$ ions.

Do not rewrite the salt $\rm AgCl$ because it is insoluble.

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of $\rm Ca^{2+}$ and two units of $\rm {NO_3}^{-}$ . Doing so will give:

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, Cl^{-}\, (aq) \to 2\, AgCl\, (s)\end{aligned}$ .

Simplify the coefficients:

$\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

7 0

2 years ago