A mole of lead will be heavier than a mole of oxygen because

Robert has 4 grams of a substance and Jill has 10 grams of the same substance. Which of the following statements is true?

ELEN [110]

If Robert has 4 grams of a substance and Jill has 10 grams of the same substance <span>Jill's sample will weigh more than Robert's sample.</span>

5 0

3 years ago

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QUESTION 3 A series of electrolytic deposition experiments is conducted. In each case, 10.0 Faradays is passed through the indiv

Neporo4naja [7]

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

Learn more: brainly.com/question/967776

6 0

2 years ago

Four research teams measured the rotation period of a newly detected neutron star, and what each team wrote in its team notebook

makvit [3.9K]

Answer:

Explanation:

The correct measurement is .710 s which is equal to .71 s so second measurement that is 0.71 s is most accurate measurement .

B. 0.71s is the most accurate .

Precision depends upon measuring instrument . Measurement by highly precise instrument has greater precision .

The measurement of 0.75 Â± 0.002s must have been taken from high precise instrument because it is capable of making measurement upto 3 decimal points .

Hence

C 0.75 Â± 0.002s is most precise measurement .

7 0

3 years ago

The concentration of carbon monoxide (CO), a common air pollutant, is found in a room to be 5.7 x 10^-3 mg/cm^3. How many grams

damaskus [11]

The amount, in mg, of CO present in the room will be 191,520 mg.

<h3>Stoichiometric problem</h3>

The concentration of the gas in the room is 5.7 x $10^{-3}$ mg/cm3.

The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.

We can obtain the volume of the room as:

350 x 300 x 320 = 33,600,000 cm3

The concentration is in mg/cm3, meaning that it is mass/volume.

Thus:

mass = concentration x volume = 5.7 x $10^{-3}$ mg/cm3 x 33,600,000 cm3

= 191,520 mg

The mass of CO in the room is 191,520 mg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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5 0

1 year ago

What is the electron configuration of an element with atomic number 20?

Vedmedyk [2.9K]

[Ar]4s^2
hope it helps

8 0

3 years ago

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