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3 years ago

A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?

Physics

2 answers:

Snowcat [4.5K]3 years ago

5 0

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

$F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N$

So, the magnitude of the vertical component of the force is 6.07 N.

Mariulka [41]3 years ago

5 0

Answer:

Vertical component of force is equal to $6.067$ N

Explanation:

The magnitude of the vertical component on any force when α is the angle between the direction of force and the X -axis is

$F_y = F * Sin\alpha$

Substituting the given values in above equation, we get -

$F_y = 35 * Sin 10\\F_Y = 35 * 0.1736\\F_Y = 6.067$

Vertical component of force is equal to $6.067$ N

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Answer:

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$K=\frac{mv^2}{2}=\frac{m^2v^2}{2m}\\$

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$r_\alpha=\frac{\sqrt{2m_\alpha K}}{(2e)B}(4)$

Dividing (4) in (3):

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