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NNADVOKAT [17]
3 years ago
8

A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?

Physics
2 answers:
Snowcat [4.5K]3 years ago
5 0

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

Mariulka [41]3 years ago
5 0

Answer:

Vertical component of force is equal to 6.067 N

Explanation:

The magnitude of the vertical component on any force when α is the angle between the direction of force and the X -axis is

F_y = F  * Sin\alpha

Substituting the given values in above equation, we get -

F_y = 35  * Sin 10\\F_Y = 35 *  0.1736\\F_Y = 6.067

Vertical component of force is equal to 6.067 N

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