Answer:
2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂
Explanation:
The balanced reaction is:
Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:
- Pb(CH₃COO)₂: 1 mole
- H₂S: 1 mole
- CH₃COOH: 2 moles
- PbS: 1 mole
In this case, to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:
- H: 1 g/mole
- S: 32 g/mole
- Pb: 207 g/mole
The molar mass of the compounds are:
- H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
- PbS: 207 g/mole + 32 g/mole= 239 g/mole
So, by stoichiometry they react and are produced:
- H₂S: 1 mole* 34 g/mole= 34 g
- PbS: 1 mole* 239 g/mole= 239 g
Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?

mass of H₂S= 2.56 grams
<u><em>2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂</em></u>
Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.
Answer:
Clarity and precision - these names are unique with each creature having only one scientific name. Helps avoid confusion created by common names. 3. Universal recognition - scientific names are standardised and accepted universally
Explanation:
Symbol: Cl
Number of Neutrons: 18
Atomic Number: 17
Melting Point: -100.98 °C (172.17 K, -149.764 °F)
Number of Protons/Electrons: 17
Atomic Mass: 35.4527 amu
Answer:
Explanation:
how many grams and moles of gold are present in 8.09 x 10^28 atoms of gold?
there are 6.02 x 10^23 molecules or atoms in 1 mole
of a compound or element
8.09 x 10^28 /(6.02 x 10^23) = 1.34 x 10^5 moles of Au
1 mole of gold (see periodic table for #79) 197 g
so 1.34 x 10^5 moles of Au weigh
197 x 1.34 x 10^5 = 2.64 x 10^7 g
your little gold treasure is worth
Gold Price Per Gram $59.87 x 2.64 x 10^7=
$$$$ 1.58 x 10^9
=$ 1,580,000,000