A reference point is a point in geometry or general which is used to determine or refer to another point. In reference to this point, measurements can be done. Like, a reference point in space is used to measure distance or displacement to another point. A reference point in time is used to measure the time interval of an event. A reference in space-time can be used to measure the speed or detect object's motion. Hence, the following points apply:

→A position from which to measure future distance

→a set of standard units for measuring displacement

→a method for determining the speed of an object

→a way to detect an object’s motion

A reference point provides a way/method to infer information about the object.

6 0

3 years ago

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A 2.0-kg object moving 5.0 m/s collides with and sticks to an 8.0-kg object initially at rest. Determine the kinetic energy lost

densk [106]

Answer:

20J

Explanation:

In a collision, whether elastic or inelastic, momentum is always conserved. Therefore, using the principle of conservation of momentum we can first get the final velocity of the two bodies after collision. This is given by;

m₁u₁ + m₂u₂ = (m₁ + m₂)v ---------------(i)

Where;

m₁ and m₂ are the masses of first and second objects respectively

u₁ and u₂ are the initial velocities of the first and second objects respectively

v is the final velocity of the two objects after collision;

From the question;

m₁ = 2.0kg

m₂ = 8.0kg

u₁ = 5.0m/s

u₂ = 0 (since the object is initially at rest)

<em>Substitute these values into equation (i) as follows;</em>

(2.0 x 5.0) + (8.0 x 0) = (2.0 + 8.0)v

(10.0) + (0) = (10.0)v

10.0 = 10.0v

v = 1m/s

The two bodies stick together and move off with a velocity of 1m/s after collision.

The kinetic energy(KE₁) of the objects before collision is given by

KE₁ = $\frac{1}{2}$ m₁u₁² + $\frac{1}{2}$ m₂u₂² ---------------(ii)

Substitute the appropriate values into equation (ii)

KE₁ = ( $\frac{1}{2}$ x 2.0 x 5.0²) + ( $\frac{1}{2}$ x 8.0 x 0²)

KE₁ = 25.0J

Also, the kinetic energy(KE₂) of the objects after collision is given by

KE₂ = $\frac{1}{2}$ (m₁ + m₂)v² ---------------(iii)

Substitute the appropriate values into equation (iii)

KE₂ = $\frac{1}{2}$ ( 2.0 + 8.0) x 1²

KE₂ = 5J

The kinetic energy lost (K) by the system is therefore the difference between the kinetic energy before collision and kinetic energy after collision

K = KE₂ - KE₁

K = 5 - 25

K = -20J

The negative sign shows that energy was lost. The kinetic energy lost by the system is 20J

3 0

4 years ago

If an object with more mass is pushed with the same force as an object with less mass the object with more mass will accelerate?

expeople1 [14]

Answer:

smaller acceleration, so lower change in velocity

Explanation:

To answer this question we examine the equation that relates mass with force and with acceleration: $F=m*a$ .

Since we want to know what happens to the acceleration, we solve for it in the equation: $a=\frac{F}{m}$

Notice that we are asked what happens when the force applied is the same, but now it is applied in an object with more mass (M).

We therefore would have to compare our initial form:

$a=\frac{F}{m}$ with the new one: $a=\frac{F}{M}$ wher the denominator is a larger quantity, therefore making our division/quotient smaller. Then, we conclude that the acceleration will be smaller, and therefore the change in velocity of the object will be lower.

5 0

3 years ago

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