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quester [9]
3 years ago
15

A 5000 kg African elephant has a resting metabolic rate of 2500 W. On a hot day, the elephant's environment is likely to be near

ly the same temperature as the animal itself, so cooling by radiation is not effective. The only plausible way to keep cool is by evaporation, and elephants spray water on their body to accomplish this. If this is the only possible means of cooling, how many kilograms of water per hour must be evaporated from an elephant's skin to keep it at a constant temperature?
Physics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

36 kg

Explanation:

To answer this question, a few assumptions have to be made:

  • That the temperature on the day is 35 °C
  • That all the heat from the elephant is goes to warming/evaporating the water on the surface of the elephant

Energy released per hour = 2500 J/s * 3600 s = 9 000 000 J

Q = mcΔT

9 000 000 J= m *4.186 J/g-K * (373K - 308K) + m*2260 J/g

m =  36 000 g = 36 kg

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Which of the following statements describes an actual orbit?
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A the moon is a satellite of earth
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3 years ago
In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pu
pashok25 [27]

Answer:

The answer is c) same.

Explanation:

When a force is applied at some point on a rigid body, the body makes a rotational movement about the axis. Said property of the force applied to rotate the body is calculated with a magnitude known as torque, which is defined as the moment of force at a capacity of that force to make a rotation around a specific point.

for case 1, the magnitude of the torque is equal to:

τ = F*(L/2)

For case 2, the torque magnitude equals:

τ = F*sin(30°) = F*(L/2)

It can be seen that in both cases it is the same torque.

7 0
3 years ago
[2.21] Please help me find a) and b)
user100 [1]

Answer:

A. 28.42 m/s

B. 41.21 m.

Explanation:

A. Determination of the initial velocity of the ball:

Time (t) to reach the maximum height = 2.9 s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)

Initial velocity (u) =?

Thus, we can obtain the initial velocity of the ball as follow:

v = u + gt

0 = u + (–9.8 × 2.9)

0 = u – 28.42

Collect like terms

u = 0 + 28.42

u = 28.42 m/s

Therefore, the initial velocity of the ball is 28.42 m/s.

B. Determination of the maximum height reached.

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)

Initial velocity (u) = 28.42 m/s.

Maximum height (h) =?

Thus, we can obtain the maximum height reached by the ball as follow:

v² = u² + 2gh

0² = 28.42² + (2 × –9.8 × h)

0 = 807.6964 + (–19.6h)

0 = 807.6964 – 19.6h

Collect like terms

0 – 807.6964 = – 19.6h

– 807.6964 = – 19.6h

Divide both side by – 19.6

h = –807.6964 / –19.6

h = 41.21 m

Therefore, the maximum height reached by the ball is 41.21 m

8 0
3 years ago
Many counties in Florida missed many school days in the fall of 2004 due to hurricanes that year. A solution for how to make up
Ivenika [448]

Answer:

108 extended days

Explanation:

Regular school hours a day = 6 hr

No. of school days to make up by extending the  regular hours = 3 days

Amount of time added to the regular hours of school = 10 min

No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.

Time of school hours in 3 days = 3\times 6= 18\,hr\,\,\,\, ;or\,\,\, (18\times 60)\,minutes

\therefore x=\frac{18\times 60}{10}

x=108\,\,days are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.

4 0
3 years ago
The loss of static electricity as electric charges transfer from one object to another is called
Vanyuwa [196]
Answer: Static discharge
6 0
2 years ago
Read 2 more answers
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