A wet electrode can cause arc blow ?

Footing: This is a 3 m wide strip footing, located on the ground surface of an isotropic, homogeneous

Rufina [12.5K]

Answer:

3

Explanation:

5 0

3 years ago

f the rope is drawn toward the motor M at a speed of vM= (5t3/2) m/s, where t is in seconds, determine the speed of the cylinder

SCORPION-xisa [38]

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED RVV

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

4 0

3 years ago

THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please

Aleksandr [31]

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

5 0

3 years ago

Consider a piston-cylinder device with a piston surface area of 0.1 m^2 initially filled with 0.05 m^3 of saturated water vapor

miv72 [106K]

The friction force f = 10000 N

The heat transfer Q = 1.7936 KJ

<u>Explanation:</u>

Given data:

Surface area of Piston = 1 $m^{2}$

Volume of saturated water vapor = 100 K Pa

Steam volume = 0.05 $m^{3}$

Using the table of steam at 100 K pa

Steam density = 0.590 Kg/ $m^{3}$

Specific heat $C_{p}$ = 2.0267 KJ/Kg K

Mass of vapor = S × V

m = 0.590 × 0.05

m = 0.0295 Kg

Solution:

a) The friction force is calculated

Friction force = In the given situation, the force need to stuck the piston.

= pressure inside the cylinder × piston area

= 100 × $10^{3}$ × 0.1

f = 10000 N

b) To calculate heat transfer.

Heat transfer = Heat needs drop temperatures 30°C.

$Q=m c_{p} \ DT$

Q = 0.0295 × 2.0267 × $10^{3}$ × 30

Q = 1.7936 KJ

3 0

4 years ago

Two gage marks are placed exactly 250 mm apart on a 12-mm-diameter aluminum rod with E 5 73 GPa and an ultimate strength of 140

NNADVOKAT [17]

Answer:

81.76 N/mm² ( MPa), 1.71233

Explanation:

Modulus of elasticity = stress / strain

stress = modulus of elastic × strain

strain = ΔL / L = 250.28 mm - 250 mm / 250 mm = 0.00112

Modulus of elasticity E = 73 GPa = 73 × 10³ MPa where 1 MPa = 1 N/mm²

E = 73 × 10³N/mm²

stress = 73 × 10³N/mm²× 0.00112 = 81.76 N/mm² ( MPa)

b) Factor of safety = maximum allowable stress / induced stress = 140 MPa / 81.76 MPa = 1.71233

8 0

4 years ago