Answer:
Expressions are made up of terms.
A term is a product of factors.
Coefficient is the numerical factor in the term
Before moving to terms like monomials, binomials, and polynomials, like and unlike terms are discussed.
When terms have the same algebraic factors, they are like terms.
When terms have different algebraic factors, they are unlike terms.
Explanation:
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Answer: Engine power is the power that an engine can put out. It can be expressed in power units, most commonly kilowatt, pferdestärke (metric horsepower), or horsepower.
Explanation: (I hope this helped!! ^^)
Heat can be diverted away from the area you want to cool using the refrigeration cycle, also known as a heat pump cycle. This is done by repeatedly compressing and expanding the working refrigerant (air, water, synthetic refrigerants, etc.) to change its pressure.
<h3>What is the cycle of a heat pump?</h3>
- In order to heat the air within a building, a heat pump warms the air outside by drawing heat from it and adding it to it. The following procedure is used to achieve this: A gas is created when liquid refrigerant absorbs heat from the ambient air in the "evaporator."
- The pressure buildup from the compressor raises the temperature of the refrigerant, just like it does with everything that is put under pressure. The refrigerant is a heated vapor, ranging in temperature from 120° to 140°F, when it exits the compressor.
- The chemical refrigerant, once transformed from a gas to a liquid state, has a remarkable capacity to absorb heat. The heat inside your house might be absorbed and released outside when the refrigerant undergoes a state shift as a result of compression and pressurization.
To learn more about Compressor refer to:
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Explanation:
We need to rearrange the following formula for the values given in parenthesis.
(1) x+xy = y, (x)
taking x common in LHS,
x(1+y)=y
(2) x+y = xy, (x)
Subrtacting both sides by xy.
x+y-xy = xy-xy
x+y-xy = 0
x-xy=-y
x(1-y)=-y
(3) x = y+xy, (x)
Subrating both sides by xy
x-xy = y+xy-xy
x(1-y)=y
(4) E = (1/2)mv^2-(1/2)mu^2, (u)
Subtracting both sides by (1/2)mv^2
E-(1/2)mv^2 = (1/2)mv^2-(1/2)mu^2-(1/2)mv^2
E-(1/2)mv^2 =-(1/2)mu^2
So,
(5) (x^2/a^2)-(y^2/b^2) = 1, (y)
(6) ay^2 = x^3, (y)
Hence, this is the required solution.
Answer:
(a) Current density at P is 
.
(b) Total current I is 3.257 A
Explanation:
Because question includes symbols and formulas it can be misunderstood. In the question current density is given as below;
where 
and 
unit vectors.
(a) In order to find the current density at a specific point <em>(P)</em>, we can simply replace the coordinates in the current density equation. Therefore
(b) Total current flowing outward can be calculated by using the relation,
where integral is calculated through the circular band given in the question. We can write the integral as below,
due to unit vector multiplication. Then,
where 
. Therefore
