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zepelin [54]
3 years ago
7

What is the measurment unit of permeability?​

Engineering
2 answers:
nikitadnepr [17]3 years ago
7 0

Answer:

Henries :)

Explanation:

I looked it up

koban [17]3 years ago
7 0

Answer:

henries

Explanation:

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What kind of value should an employee possess when employees are expected to be responsible and fair?
jasenka [17]

Answer:

E self-confidence

Explanation:

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3 years ago
A type of adjustable square that can be used to set, test, and transfer angles is called a
bekas [8.4K]

Answer:

pocket cut

Explanation:

type of adjustable square that can be used to set test and transfer angles. sliding t bevel.

5 0
2 years ago
3. (9 points) A square-thread power screw is used to raise or lower the basketball board in a gym, the weight of which is W = 10
Bezzdna [24]

Answer:

a) 49.95 watts

b) The self locking condition is satisfied

Explanation:

Given data

weight of the square-thread power screw ( w ) = 100 kg = 1000 N

diameter (d) = 20 mm ,

pitch (p) = 2 mm

friction coefficient of steel parts ( f ) = 0.1

Gravity constant ( g ) = 10 N/kg

Rotation of electric power screwdrivers = 300 rpm

A ) Determine the power needed to raise to the basket board

first we have to calculate T

T = Wtan (∝ + Ф ) * \frac{Dm}{2} ------------- equation 1

Dm = d - 0.5 ( 2) = 19mm

Tan ∝ = \frac{L}{\pi  Dm}  where L = 2*2 = 4

hence ∝ = 3.83⁰

given f = 0.1 , Tan Ф = 0.1.     hence Ф = 5.71⁰

insert all the values into equation 1

T = 1.59 Nm

Determine the power needed using this equation

\frac{2\pi NT }{60}   =  \frac{2\pi * 300 * 1.59}{60}

= 49.95 watts

B) checking if the self-locking condition of the power screw is satisfied

Ф > ∝  hence it is self locking condition is satisfied

3 0
2 years ago
A spherical seed of 1 cm diameter is buried at a depth of 1 cm inside soil (thermal conductivity of 1 Wm-1K-1) in a sufficiently
postnew [5]

Answer:

Find the attachment for the answer

8 0
3 years ago
A sample of wastewater is diluted 10 times. The diluted solution has an ultimate biochemical oxygen demand (BOD), Lo, of 30 mg/L
zzz [600]

Answer:

474.59 mg/L

Explanation:

Given that

BOD = 30 mg/L

Original BOD  = 30 mg/L × dilution factor

Original BOD  = 30 mg/L  × 10 = 300 mg/L

L_o = \frac{BOD}{1-e^{-5t}}

here L_o is the ultimate BOD ; BOD is the  biochemical oxygen demand ;  t = 0.20 /day

L_o = \frac{300}{1-e^{-5(0.20)}}

L_o = 474.59 \ mg/L

3 0
3 years ago
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