Answer:
Explanation:
Given that diameter of tube= 20 mm
flow rate = 72 lt/hr
The properties of SAE 30 oil at 30°C
We know that volume flow rate Q= AV
V= 0.064 m/s
Now lets find Reynolds number to check the type of flow
Re=7.18 So we can say that this is laminar flow and we know that pressure drop for laminar flow is given as
Now by putting the values the pressure drop for per unit length
Answer: speaks Portuguese
Eu disse a todos a tradução para que possam te ajudar
Explanation: Y’all can help I have no idea
QUESTION 13. Explain the use of quotation marks in the excerpt "I will give each of you
seed. The one who will bring me the most beautiful flower within six months will be chosen but
wife and the future empress of China. ".
QUESTION 14. The palace servant considered the idea of her daughter attending the celeb
organized by the prince of the region, a foolish idea, a madness. This is an OP
Do you agree with this opinion of the character? Justify your answer.
Answer:
the given statement is true.
Explanation:
Given Information:
ZΩ = 9 per phase
Sbase = 75 MVA
Sbase = 100 MVA
kV = 27 kV
kV = 30 kV
Required Information:
Zpu = ?
Zpu_new = ?
Answer:
Zpu = 0.925 pu
Zpu_new = 1 pu
Explanation:
Zbase = (kVbase)²/Sbase
Zbase = (27x10³)²/75x10⁶
Zbase = 9.72
Zpu = Zactual/Zbase
Zpu = 9/9.72
Zpu = 0.925 pu
Now base MVA is changed to 100 MVA and base kV is changed to 30kV so the per unit value becomes
Zbase = (kVbase)²/Sbase
Zbase = (30x10³)²/100x10⁶
Zbase = 9
Zpu_new = Zactual/Zbase
Zpu_new = 9/9
Zpu_new = 1 pu
Answer:
293 kg
Explanation:
Let's say the tension in each cable is Tb, Tc, and Td.
First, find the length of cable AD:
r = √(2² + 2² + 1²)
r = 3
Using similar triangles:
Tdx = 2/3 Td
Tdy = 2/3 Td
Tdz = 1/3 Td
Sum of the forces in the x direction:
∑F = ma
Tb − 2/3 Td = 0
Td = 3/2 Tb
Sum of the forces in the y direction:
∑F = ma
2/3 Td − Tc = 0
Td = 3/2 Tc
Sum of the forces in the z direction:
∑F = ma
1/3 Td − mg = 0
Td = 3mg
From the first two equations, we know Td is greater than Tb or Tc. So we need to set Td to 8.6 kN, or 8600 N.
8600 N = 3mg
m = 8600 N / (3 × 9.8 m/s²)
m ≈ 292.5 kg
Rounded to three significant figures, the maximum mass of the crate is 293 kg.
