The force that causes centripetal acceleration of a car making a turn on a flat road is friction
The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.
Fc = f
m v² / r = μ N
Fc ∝ 1 / r
The larger the centripetal force the the smaller the radius of curvature.
Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction
To know more about centripetal force
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Answer:
The thermal energy is carried by electromagnetic waves
Explanation:
There are three types of transfer of heat (thermal energy):
- Conduction: conduction occurs when two objects/two substances are in contact with each other. The heat is transferred from the hotter object to the colder object by the collisions between the molecules of the two mediums.
- Convection: convection occurs when a fluid is heated by an external source of heat. The part of the fluid closer to the heat source gets warmer, therefore it becomes less dense and it rises, and it is replaced by the colder part of the fluid, which is colder. Then, this part of fluid is heated as well, so it gets warmer, it rises, etc.. in a cycle.
- Radiation: radiation occurs when thermal energy is carried by electromagnetic waves. Since electromagnetic waves do not need a medium to propagate, this is the only method of heat transfer that can occur through a vacuum (so, in space as well).
Indeed, the Sun emits a lot of electromagnetic radiation, which travels through space and eventually reaches the Earth, heating it.
From Newton's Three Laws of Motion, derived formulas are already conveniently presented for a rectilinear motion at constant acceleration. One of its equations is
y = (Vf² - Vi²)/2a, where
y is the vertical height travelled by the object
Vf is the final velocity
Vi is the initial velocity
a is the acceleration
Now, when a man jumps, the only force acting on him is gravity pulling him down. When he reaches his maximum height, eventually his velocity will reach zero. So, Vf = 0. Suppose all parameters with subscript 1 refers to man jumping on Earth and those with subscript 2 refers to the man jumping on moon. Since initial velocity and angle is said to be the same, when we find the ratio of x₂/x₁, the terms (Vf²-Vi²) cancels out leaving us with
x₂/x₁ = a₂/a₁
It is common knowledge that gravity on Earth is 9.81 m/s². According to literature, the gravity on the moon is 1.62 m/s². Thus,
x₂/x₁ = a₁/a₂ = 9.81/1.62 = 6
x₂ = 6x₁
Therefore, the man jumping on the moon can reach 6 times higher than in Earth.
Answer:
answer
Explanation:
it is the answer which was presented in the year
Answer:
0.198 m/s
Explanation:
m1 = 0.7 kg, u1 = 0.15 m/s,
v1 = 0.08 m/s
m2 = 0.5 kg, u2 = 0.1 m/s
Let the speed of 0.5 kg is v2 after the collision.
By using the conservation of momentum
Momentum before collision = momentum after collision
m1 u1 + m2 u2 = m1 v1 + m2 v2
0.7 x 0.15 + 0.5 x 0.1
= 0.7 × 0.08 + 0.5 × v2
0.099 = 0.5 v2
v2 = 0.198 m/s
