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likoan [24]
3 years ago
13

After an ice storm, ice falls from one of the top floors of a 65-story building. The ice falls freely under the influence of gra

vity. Which one of the following statements concerning this situation is true?a) The kinetic energy of the ice increases by equal amounts for equal distances.
b) The kinetic energy of the ice increases by equal amounts for equal times.
c) The potential energy of the ices decreases by equal amounts for equal times.
d) The total energy of the block increases by equal amounts over equal distances.
e) As the block falls, the net work done by all of the forces acting on the ice is zero joules.
Physics
1 answer:
adell [148]3 years ago
7 0

Answer:

The correct answer is a) The kinetic energy of the ice increases by equal amounts for equal distances.

Explanation:

The law of conservation states that the energy cannot be created nor be destroyed but can be converted from one form to another.Before the ice even starts falling we already know that it possesses energy in the form of potential energy given by P=mgh where m is the mass of the ice , g is the acceleration due to gravity and h is the height of the ice above the ground whatever that may be, since a number is not given here.As the ice falls the energy is converted from potential energy to kinetic energy. We notice one thing about the equation for the potential energy P , which is that it is not only directly proportional to h but also is linear in h as well(which is the main reason why a) is correct) which means that if the ice drops by 1 meter the potential energy it will have lost would be ΔPE=mgΔh=-mg, where Δh is the change in its height which is 1 meter here.And according to the principle of conservation of energy this energy must be converted to kinetic energy so the ΔKE=-ΔPE=mg, and this process repeats and for each meter it falls, it picks up the same amount of kinetic energy equaling mg(which is the same as the loss in PE per each meter of fall). So a 2 meter decrease in height will result in an increase in KE of 2mg, a 3 meter decrease in height will result in an increase in KE of 3mg. gain in kinetic energy only depends on the drop in height, which is true irrespective of where the ice might happen to be in its journey close to the top or the bottom. So the drop in height of lets say x at any point in the journey will result in the same increase in KE = ΔKE = mgx. Which proves part a) to be correct.

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Solutes

Explanation:

These cleaning agents and additives are examples of solutes.

  • Solutes are substances that dissolves in other substances called solvents to form a solution.
  • The solutes are the cleaning agents and anti-knock additives.
  • The solvents are the gasoline.
  • When solutes dissolves in solvents they form solutions.
  • A solution is a mixture that is homogeneous.
  • For a solute dissolve in a solvent, they must both have the same property.
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learn more:

Heterogeneous mixtures brainly.com/question/1446244

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Kieran takes off from rest down a 50 m high, 10° slope on his jet-powered skis. The skis have a thrust of 280 N parallel to the
xz_007 [3.2K]

Answer:0.46

Explanation:

Given

Initial height h=50 m

inclination \theta =10^{\circ}

Thrust=280 N

combined mass of kieran and skis m=50 kg

Speed at the bottom v=40 m/s

From Work Energy Theorem

Work done by all the force is equal to change in kinetic Energy

W_{gravity}+W_{friction}+W_{thrust}=\frac{1}{2}mv^2-0------------1

distance traveled along the slope x=\frac{50}{\sin 10}=287.93 m

W_{gravity}=mgh=50\times 9.8\times 50=24500 J

W_{thrust}=F\times x=280\times 287.93=80,620.4 J

W_{friction}=-\mu mg\cos 10

substitute in 1

24,500+80,620.4+W_{friction}=\frac{1}{2}\times 50\times 1600

W_{friction}=40,000-24,500-80,620.4

-\mu \cdot 50\times 9.8\times 287.93=-65,120.4

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Part C: Quantitative Problems when vf is not 0
Alina [70]

Answer:

(a)

\triangle v=-8\ m/s\\\triangle mv=-56\ kg.m/s

(b)

1120 N

Explanation:

Change in velocity, \triangle v is given by subtracting the initial velocity from the final velocity and expressed as \triangle v= v_f -v_i

Where v represent the velocity and subscripts f and i represent final and initial respectively. Since the ball finally comes to rest, its final velocity is zero. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by

\triangle v=0-8=-8\ m/s

To find m\triangle v then we substitute 7 kg for m and -8 m/s for \triangle v therefore \triangle\ v=7 Kg\times -8 m/s=-56\ Kg.m/s

(b)

The impact force, F is given as the product of mass and acceleration. Here, acceleration is given by dividing the change in velocity by time ie

a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}

Substituting t with 0.05 s then a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}=\frac {-8}{0.05}=-160 m/s^{2}

Since F=ma then substituting m with 7 Kg we get that F=7*-160=-1120 N

Therefore, the impact force is equivalent to 1120 N

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Answer: the one spinnin

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