Answer
given,
ω₁ = 0 rev/s
ω₂ = 6 rev/s
t = 11 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
11 α = 6 - 0
= 0.545 rev/s²
The angular displacement
θ₁= ωi t + (1/2) α t²
θ₁= 0 + (1/2) (0.545)(11)^2
θ₁= 33 rev
case 2
ω₁ = 6 rev/s
ω₂ = 0 rev/s
t = 14 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
14 α = 0 - 6
= - 0.428 rev/s²
The angular displacement
θ₂= ωi t + (1/2) α t²
θ₂= 6 x 14 + (1/2) (-0.428)(14)^2
θ₂= 42 rev
total revolution in 25 s is equal to
θ = θ₁ + θ₂
θ = 33 + 42
θ = 75 rev
The gravitational constant was experimentally measured by W Cavendish using the attraction between big and small lead balls. is true
The correct answer is true
<h3>How do you define gravitational constant?</h3>
the strength of gravity. a factor in use in Newton's gravity law to relate the strength of the gravitational pull between two bodies with their masses and distance from one another. 6.67259 X 10-11 newtons per square kilogram is roughly the gravitational constant. G is its identifier.
<h3> where is the strongest gravity is?</h3>
The gravitational pull of the earth is greatest near sea level, normally, and weakens as you get further from the center, such as to the summit of Mt. Everest. Because the obloid earth was slightly wider, but only by a minor ratio, the gravity just at poles is stronger than that at the equator.
To know more about gravitational constant visit:
brainly.com/question/858421
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It takes about a really long time
Explanation:
Hey there!!
Let's simply work with it.
Here,
load = 1200N
Effort = 200N
Load distance = 15cm
We have,
According to the principle of lever.
L×LD = E×ED.
1200×15 = 200× ED.
18000 = 200ED.
Therefore, Effort Distance = 90cm.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
A=60.06 x 10⁻⁵ m²
Explanation:
Given that
Weight of the person = 864 N
Weight of the bike = 85 N
The total weight ,car + bike ,Wt= 864 + 85 N
Wt = 949 N
2 p = 949 N
The weight on the each tire(F) = 474.5 N
P = 7.9 x 10 ⁵ Pa
We know that
Force = Pressure x Area
F= P A
By putting the values
474.5 = 7.9 x 10 ⁵ A
A=60.06 x 10⁻⁵ m²
Therefore area of contact A
A=60.06 x 10⁻⁵ m²
