The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
C) $281.25
Step-by-step explanation:
3/15 describes you having to pay the bill in 15 days with a 3% discount.
3% = 0.03
289.95 - (298.95 x 0.03)
289.95 - 8.6985
281.25
<h2><u>
Answer:</u></h2>
x = 3
y = -8
<h2><u>
Step-by-step explanation:</u></h2>
x + y = -5
x - y = 11
Since the y's will cancel out, we don't need to modify the two equations in any way.
Now, just add the two equations.
x + x = 2x
y + (-y) = 0
-5 + 11 = 6
2x = 6
Divide by 2.
x = 3
To find y, plug 3 in as "x" in one of the two equations.
3 + y = -5
y = -8
Answer: ones place
Step-by-step explanation:
One tenth of ten is one