All categories

2 years ago

2/6, 5/12, 3/7, and 4/10. List least to most

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

7 0

Turn them into percentages:
2/6=1/3=33.333%
5/12=42%
3/7=43%
4/10=2/5=40%

Now put them in order :)

2/6,4/10,5/12,3/7

You might be interested in

List the fractions in descending order of 2/5 8/9 4/5 1/3 3/10

snow_lady [41]

Answer:

8/9, 4/5, 2/5, 1/3, 3/10

Step-by-step explanation:

2/5 = 0.4 8/9 = 0.888 4/5 = 0.8 1/3 = 0.333 3/10 = 0.3

8 0

2 years ago

An equation parallel and perpendicular to 4x+5y=19

mestny [16]

Answer:

An equation parallel to 4x + 5y = 19 would be y = -4/5x +12.

An equation perpendicular to 4x + 5y = 19 would be y = 5/4x + 10.

Step-by-step explanation:

The equation given represents a linear equation in Standard Form (Ax + By = C). Lines that are parallel to each other go the same direction and don't touch, so their slopes must be the same. However, lines that are perpendicular go in opposite directions and intersect, so their slopes must be the direct opposite of each other. In order to find the slope, you must first convert from the Standard Form given to Slope Intercept Form (y = mx +b). When you solve the given equation for 'y', you get: y = -4/5x + 19, where the slope = -4/5. To make a parallel equation, simply keep the same slope and choose a different y-intercept ('b'). To make a perpendicular equation, take the direct opposide of your slope 5/4 (positive) and choose a different y-intercept.

8 0

2 years ago

Marvin was taking a Bicycle ride the graph represents his route he started from his home represented by point a on the graph and

DedPeter [7]

Point A is (3, 2) and Point B is (8, 7)

7 0

2 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago

The Sanchez family is planning a party. They want to budget spending $25 per guest. They already spent $200 on supplies and will

OverLord2011 [107]

Answer:

Step-by-step explanation:

20×25 = 500

20 guest

25 dollars per guest

75s+200= 500

75s = 300

S = 4

They can afford to buy 4 cases of snacks and stay within their budget.

3 0

2 years ago