2/6, 5/12, 3/7, and 4/10. List least to most

Can someone please help me with these

OLga [1]

Answer:

1. 1072.6

2. 753.6

3. 194.2

4. 59.5

5. 4848.3

6. 1818.3

Step-by-step explanation:

We have to use the trigonometric functions sin, cos, and tan. Remember the mnemonic SOH-CAH-TOA when solving these problems. (sinθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse, tanθ=opposite/adjacent)

1. tan(40)=900/x

x=900/tan(40)

x=1072.6

2. tan(37)=x/1000

1000tan(37)=x

753.6=x

3. sin(18)=60/x

x=60/sin(18)

x=194.2

4. sin(48)=x/80

80sin(48)=x

59.5=x

5. tan(22)=x/12000

12000tan(22)=x

4848.3=x

6. tan(33)=x/2800

2800tan(33)=x

1818.3=x

7 0

3 years ago

Can i get some help please??? Thanks!!!!

Musya8 [376]

Answer: try 34

Step-by-step explanation:

8 0

3 years ago

What is the product (2x + 3y) (7x – 4y)?

cupoosta [38]

Answer:

14x²-12y²

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable X as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

Thus, the expected value of the temperature increase is 17.5°C.

7 0

4 years ago

Element X is a radioactive isotope such that every 90 years, its mass decreases by half. Given that the initial mass of a sample

steposvetlana [31]

Answer:

approximately 27 grams

Work Shown:

Half life formula

y = A*(0.5)^(x/H)

where,

A = starting amount = 30 grams

H = half life period = 90 years

x = number of years that pass by = 12

y = amount left over after x years

Let's plug the values for x, A and H into the formula to find y

y = A*(0.5)^(x/H)

y = 30*(0.5)^(12/90)

y = 27.3516746567466

y = 27 .... rounding to the nearest whole number

4 0

3 years ago