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aliya0001 [1]
3 years ago
13

List the Earth names for the 30 alien elements in order of atomic number

Chemistry
1 answer:
mariarad [96]3 years ago
6 0
Pfsst
bombal
chow
ddoggone
ernst
floxxit
goldy
nuutye
apstrom
logon
byyou
zapper
yazzer
highho
magnificon
oz
fratt
jeptum
quackzil
doadeer
rhaap
terriblum
sississ
urrp
vulcania
wobble
xtalt
pie
anatom
eldorado  (I think these are the answers)
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3 years ago
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sergeinik [125]

Answer:

Bohr model A

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3 years ago
What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

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3 years ago
Use the periodic table to select which type of bond is present and which of the listed properties is most likely for each substa
jenyasd209 [6]

Answer:

A = Metallic Bond

B = Strong bonding, strong conductor, high melting and boiling points

Explanation:

Since the bond is between two metals (located in groups 11 and 12), they would experience metallic bonding. Metallically bonded molecules have high melting and boiling points due to the strength of the metallic bond. They also experience strong electrical current due to the there delocalized electrons.

3 0
3 years ago
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