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Gnom [1K]
3 years ago
6

What is the magnitude of the centripetal force that must be applied in order for a 2kg ball on a 2.0 m string to spin with unifo

rm circular motion at 5.0 m/s
Physics
2 answers:
NeTakaya3 years ago
6 0

The ball needs to accelerate with a magnitude <em>a</em> (pointed towards the center of the circle) of

<em>a</em> = (5.0 m/s)² / (2.0 m) = 12.5 m/s²

Then the required tension <em>F</em> in the string would need to be

<em>F</em> = (2 kg) (12.5 m/s²) = 25 N

bezimeni [28]3 years ago
5 0
Because centripetal force equals mv^2/r, we can plug in our known values to result in (2(5)^2)/2, which is equal to 25 n.
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Suppose an unknown substance has a melting temperature of 1,200 degrees Celsius and a density of 16.7 g/cm3. However, the differ
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A 4. 0 g sample of ra-226 decays to 1. 0 g. if the half-life of ra-226 is 1620 years, how much time has elapsed?
charle [14.2K]

The time elapsed is 3229.2 days.

First-order reactions include those in radioactive decay. The reduction in radioactive nuclei per unit of time is the rate of decay, or activity, of a sample of a radioactive substance.

The Radioactive Formula is given by

                                N = N₀ (\frac{1}{2} )^\frac{t}{T}

Where N₀ = The initial quantity of the substance.

           N = The quantity remained.

           T = the half-life of the decaying quantity.

           t = time elapsed

The initial quantity of the substance = 4.0 g

The quantity remained = 1.0 g

The half-life of the decaying quantity = 1620 years

Using formula;

                1.0 = 4.0 (\frac{1}{2} )^\frac{t}{1620} \\

                log \frac{1.0}{4.0} = \frac{1}{1620} log \frac{1}{2}\\

                log 0.25 = \frac{t}{1620} log 0.5\\

                -0.60 = \frac{t}{1620} (-0.301)\\

                  t = \frac{972}{0.301} \\

                  t= 3229.2 sec

Therefore, the time elapsed is 3229.2 days

Learn more about radioactive here:

brainly.com/question/23566209

#SPJ4

7 0
2 years ago
Two 0.50 gg spheres are charged equally and placed 2.5 cmcm apart. When released, they begin to accelerate at 170 m/s2m/s2 . Wha
anygoal [31]

Answer:

q = 76.8*10⁻⁹ C = 76.8 nC

Explanation:

Assuming no other forces acting on the charges, and that both spheres must be considered as point charges (and as point masses as well) , the force that is responsible for the initial acceleration is the electrostatic force, which obeys Coulomb´s Law.

According to Newton´s 2nd Law, this force is related with the mass and the acceleration as follows:

F = m*a = 0.0005 kg * 170 m/s2 = 0.085 N

This same force, expressed as the electrostatic force, is as follows:

F = \frac{k*q^{2}}{(.025m)^{2}}

As both expressions for F are equal each other, we can solve for q:

q =\sqrt{\frac{(.085N)*0.025 m2^{2}}{9*109} }

⇒ q = 76.8*10⁻⁹ C = 76.8 nC

7 0
4 years ago
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