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krek1111 [17]
3 years ago
8

Convert 477°C to degrees Fahrenheit.

Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
5 0

Answer:

890.6

Explanation:

(477°C × 9/5) + 32 = 890.6°F

katovenus [111]3 years ago
5 0
Answer 890.6

Explaining:
477 x 9/5 + 32= 890.6
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A student is building an electrical circuit. Which material should she choose for wires, and why.
r-ruslan [8.4K]

D. A metal such as copper, because its atom have very mobile electrons         - A-p-e-x verified!

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3 0
3 years ago
How many hydrogen atoms are in 5 molecules of isopropyl alcohol, c3h7o?
Oduvanchick [21]
1 molecule of C3H7O has 7 atoms of hydrogen (remember that the numbers to the right of each symbol ara subscripts and they indicate the number of atoms of that element in the molecular formula).

Then 5 molecules will have 5 * 7 atoms of hydrogen.

5 * 7 = 35.

Then the answer is that there are 35 atoms of hydrogen in 5 molecules of isopropyl alcohol, C3H7O
7 0
3 years ago
Read 2 more answers
How many grams of sodium nitrate. NaNO3, are soluble in 100
natka813 [3]

Answer:

Your correct answer is D. 40 g

Explanation:

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4 0
3 years ago
Read 2 more answers
What fraction of a Sr-90 sample remains unchanged after 87.3 years
jolli1 [7]
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
8 0
3 years ago
If 2.00 g of N2 occupies 1.25 L space, how many moles of N2
uranmaximum [27]

Answer:

n₂ =1.4 mol

Explanation:

Given data:

Mass of nitrogen = 2 g

Initial Volume occupy by nitrogen = 1.25 L

Final volume occupy by nitrogen = 25.0 L

Final number of moles = ?

Solution;

Formula:

V₁ / n₁ = V₂ / n₂

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 2 g/ 28 g/mol

Number of moles = 0.07 mol

Now we will put the values in formula:

V₁ / n₁ = V₂ / n₂

n₂ = V₂× n₁ /V₁

n₂ = 25 L × 0.07 mol /  1.25 L

n₂ = 1.75 L. mol / 1.25 L

n₂ =1.4 mol

7 0
3 years ago
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