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krek1111 [17]
3 years ago
8

Convert 477°C to degrees Fahrenheit.

Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
5 0

Answer:

890.6

Explanation:

(477°C × 9/5) + 32 = 890.6°F

katovenus [111]3 years ago
5 0
Answer 890.6

Explaining:
477 x 9/5 + 32= 890.6
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Help pls do the last two all work and last two questions
andrew11 [14]

d1 = 15 miles

t1 = 1 hour

d2 = 25 miles

t2 = 2 hours

d = 15 + 25 = 40 miles

t = 1 + 2 = 3 hours

avg. \: speed \:  =  \:  \frac{total \: distance}{total \: time}

avg. \: speed \:  =  \frac{40}{3}

avg. \: speed \:  = 13.33mi \: hr ^{ - 1}

8 0
3 years ago
Which chemical property makes a substance suitable as a fuel?
inessss [21]
<span> Ethanol's </span>chemical<span> formula is C2H5OH.</span>Properties<span>. Pure ethanol is a flammable, colorless liquid with a boiling point of 78.5° C. Its low m</span>
4 0
4 years ago
Read 2 more answers
The atomic mass of element A is 35.45 amu. A 28.54 g sample of A combines with 85.42 g of another element B to form a compound A
vodka [1.7K]

The atomic mass of element B is 106.1 amu.

Given:

  • The atomic mass of element A is 35.45 amu.
  • A +B → AB
  • 28.54 g sample of A combines with 85.42 g of another element B

To find:

The atomic mass of element B.

Solution:

The mass of element A = 28.54 g

The atomic mass of element A = 35.45 amu = 35.45 g/mol

Moles of element A :

= \frac{28.54 g}{35.45 g/mol}=0.8051 mol

A +B → AB

According to reaction, one mole of A combines with 1 mole of B , then 0.8051 moles of A will combine with:

=\frac{1}{1}\times 0.8051 mol=0.8051 \text{ mol of B}

Moles of B element = 0.8051 mol

Mass of element B used = 85.42 g

The atomic mass of element B =M

0.8051 mol=\frac{85.42 g}{M}\\M=\frac{85.42 g}{0.8051 mol}=106.1 g/mol = 106.1 amu

The atomic mass of element B is 106.1 amu.

Learn more about moles of substance here:

brainly.com/question/2293005?referrer=searchResults

brainly.com/question/2293228?referrer=searchResults

3 0
3 years ago
A small coffee cup calorimeter contains 28.0 g of H2O at 19.73 oC. A 2.05 g sample of a metal alloy is heated to 98.88 oC and th
Alborosie

Answer:

1.104 J/g°C

Explanation:

Using Q = m × c × ∆T

Where;

m = mass of substance (g)

c = specific hear capacity (J/g°C)

∆T = change in temperature (°C)

For a colorimeter,

Q(water) = - Q(metal)

m. c. ∆T (water) = - m. c. ∆T (metal)

According to the information provided;

For water:

m = 28.0g

c = 4.184 J/g°C

∆T = (21.23 - 19.73°C)

For the metal:

m = 2.05g

c = ?

∆T = (21.23 - 98.88°C)

m. c. ∆T (water) = - m. c. ∆T (metal)

[28 × 4.184 × (21.23 - 19.73°C)] = -[2.05 × c × (21.23 - 98.88°C)]

[117.152 × 1.5] = -[2.05 × c × (-77.65)]

175.728 = -[-159.1825c]

175.728 = 159.1825c

c = 175.728 ÷ 159.1825

c = 1.104

c = 1.104 J/g°C

8 0
3 years ago
What is the length (in cm) of the side of an iron ingot (rectangular box) that has a mass of 4.578 kg and has width = height = 5
AfilCa [17]
Since we have the mass of the iron ingot we can get its volume by dividing the mass (4.578) by the density of iron (7874 kgm^-3) and we get that the volume is 5.8140716x10^-4 m^3. now we convert the volume from m^3 to cm^3(1m^3=1000000cm^3) and so by multiplying  5.8140716x10^-4 by <span>1000000 we get:581.4cm^3 (1 decimal place).

the volume for any  cuboid is V=l x w x s we have the volume, the length and the  width, so we plug in the values and solve for s
</span>s= \frac{581.4}{5^{2} } =23.3cm
 the answer is rounded to three significant figures

hope i helped
5 0
4 years ago
Read 2 more answers
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