What is the equilibrium constant of a reaction?
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Answer 1) To find the hybridization of carbon we need to draw the lewis structure first; which is attached in the answer.
So the formula for finding hybridization is
Lone pairs + Bonding pairs = hybridisation.
Here, in the molecule of methionine Carbon is bonded to all 4 atoms and has got no lone pairs so we will have;
0 + 4 = 4 which means it is
hybridized.
Answer 2) For oxygen we can see in the lewis structure that it is having 2 lone pairs and double bonded with carbon atom, also there is another oxygen atom with two lone pair but bonded with carbon and hydrogen at the end.
So, in both the cases we can calculate;
where 2 lone pairs are present
2 + 2 = 4 so, it will be hybridized.
So, Oxygen is also hybridized.
Answer 3) Nitrogen present in the methionine is bonded to carbon atom and hydrogen atoms and has only one lone pair on it.
So when we are substituting this in the formula we get 1 + 3 = 4;
which means 1 lone pair and 3 bond pairs so, it is also hybridized.
Answer 4) Sulfur atom in methionine is bonded to two carbon atoms forming a linear structure with 2 lone pairs on it.
So, it has 2 lone pairs and 2 bond pairs,
hence the hybridization will be hybridized.
As, 2 + 2 = 4 which means it is hybridized.
So the formula for finding hybridization is
Lone pairs + Bonding pairs = hybridisation.
Here, in the molecule of methionine Carbon is bonded to all 4 atoms and has got no lone pairs so we will have;
0 + 4 = 4 which means it is
Answer 2) For oxygen we can see in the lewis structure that it is having 2 lone pairs and double bonded with carbon atom, also there is another oxygen atom with two lone pair but bonded with carbon and hydrogen at the end.
So, in both the cases we can calculate;
where 2 lone pairs are present
2 + 2 = 4 so, it will be
So, Oxygen is also
Answer 3) Nitrogen present in the methionine is bonded to carbon atom and hydrogen atoms and has only one lone pair on it.
So when we are substituting this in the formula we get 1 + 3 = 4;
which means 1 lone pair and 3 bond pairs so, it is also
Answer 4) Sulfur atom in methionine is bonded to two carbon atoms forming a linear structure with 2 lone pairs on it.
So, it has 2 lone pairs and 2 bond pairs,
hence the hybridization will be
As, 2 + 2 = 4 which means it is
Number of particles inside a sugar bowl = 4.4 x 10²³
<h3>Further explanation</h3>Given
The molar mass of sugar = 342.3 g/mol
mass of sugar = 250 g
Required
Number of particles
Solution
1 mol = 6.02 x 10²³ particles
mol of sugar :
mol = 250 g : 342.3 g/mol = 0.73 mol
Number of particles :
N = n x No
N = 0.73 x 6.02 x 10²³
N = 4.39 x 10²³ ≈ 4.4 x 10²³
Answer : The initial rate for a reaction will be
Explanation :
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to A
b = order with respect to B
c = order with respect to C
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 1 from 2, we get:
Dividing 1 from 3, we get:
Dividing 3 from 4, we get:
Thus, the rate law becomes:
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
Now we have to calculate the initial rate for a reaction that starts with 0.75 M of reagent A and 0.90 M of reagents B and C.
Therefore, the initial rate for a reaction will be