Answer:
Atoms with<u>2</u>or less electrons in the outermost level tend to lose electrons
Ca^2+ and I^-
Na+ and Co3^2-
Ga^3+ and ClO3
Cu^2+ and F-
NH4^- and PO4^3-
Fe2+ and (SO4)^2-
Mg2+ and NO3^-
NH4^+ and NO2^-
K^+ and (C2H3O2)^- {C2H3O2 is acetate}
Na^+ and Cr2O7^2-
Answer: (E) 300 bq
Explanation:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.
Half life is represented by 
Half life of Thallium-208 = 3.053 min
Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e.
, after second half life, the activity would be reduced to half of 1200 i.e.
, and after third half life, the activity would be reduced to half of 600 i.e.
,
Thus the activity 9 minutes later is 300 bq.
Answer : The correct answer is 74.83 m/s .
The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

Where KE = kinetic energy in J or
m = mass in Kg v = speed in m/s²
Unit of KE is Joules (J) .
Givne : KE = 2100 J mass = 0.75 kg v = ?
Plugging value in KE formula =>


Dividing both side by 0.375 kg =>



Answer: Dissolve approximately 3 mg of Sodium Chloride in 2 mL of water.
Add 0.4 mL of silver nitrate TS and acidify with diluted nitric acid.