Volume = 22.4 dm3
n = 2 mol of H2
n = 1 mol of N2
Temperature = 273.15
All H2 reacts
reaction
N2 + 3H2 = 2NH3
1:3 ratio
Calculation:
N2 initial - N2 reacted = Final N2
1 - 2*(1/3) = 0.3333 mol of N2 left
H2 = 0 left
NH3 formed = 2/3*1 = 2/3 = 0.666
Total mol:
0.3333 + 0.666 = 1 mol
Apply the equation :
PV = nRT
P = nRT/V = 1*0.0082*(273.15)/(22.4) = 0.0999924 atm
PH2 = 0
PN2 = 1/3*0.0999924 = 0.0333308 atm
PNH3 = 2/3*0.0999924 = 0.0666616 atm
Answer is 0.0666616 atm
B. the number 3.
there are 2Al's on both sides and 6 Cl's on the right side so to balance it, you multiply Cl2 by 3 to get 6 Cl's.
The balanced equation is:
Then proceed with the following equations.
The answer is
.
Answer: Charles's law, Avogadro's law and Boyle's law.
Justification:
Boyle's law states that at constant temperature PV = constant
Charles law states that at constant pressure V/T = constant
Avogadro's law states that at constant pressure ant temperature, equal volume of gases contain equal number of moles: V/n = constant
Ideal gas law states PV/nT = constant => PV = nT*constant = PV = nTR
