(a) need to find the number of books, we'll call it "b". then the money (6w) minus the cost of books (17b) equals change left over (w)
6w - 17b = w
6w - w = 17b
5w = 17b
(5/17)w = b
(b) if w = 34
(5/17) *34 = b
10 = b
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now we can rewrite this expression as<u>
, which is your final answer.</u>
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
From 1 to 100, there are 50 pairs that has the sum is 101
Z=101×50=5050
4. We can see that
1-2=-1
3-4=-1
5-6=-1
...........
and so on
There are 10 pairs that has sum is -1
Z= 10×(-1)=-10
Answer:
150 miles
Step-by-step explanation:
If you go 50 more miles after you have gone 100, you have traveled a total of ...
100 + 50 = 150 . . . miles
1.) The error is that she attached the
variable with the flat fee (which is
constant) and put the daily rent as a
constant (which is variable).
The correct equation is:
365+125x=250+175x
2.) N=5
3.) k=-35.
Explanation: Solution:
17k-6=37k+4 . 17k-37k=4+6 .
-27k=10 . k=10\cdot(7-2) . k=-35 .
4.)

.