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velikii [3]
2 years ago
7

If the heat of fusion of water is 80 cal/g, the amount of heat energy required to change 15.0 grams of ice at 0°C to

Chemistry
1 answer:
kicyunya [14]2 years ago
4 0

Answer:

1200 cal

Explanation:

80 cal/g * 15 g = 1200 cal

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When a liquid is heated, the temperature stops rising at the liquid’s ____________________.
Agata [3.3K]

Hi there,

the answer to the blank is: boiling point

When a liquid is heated, the temperature stops rising at the liquid's boiling point.

Hope this is correct :)

Have a great day

5 0
3 years ago
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Calculate the molar solubility of copper(II) arsenate (Cu3(AsO4)2) in water. Use 7.6 x 10^-36 as the solubility product constant
Molodets [167]
Molar solubility<span> is the number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated. We calculate as follows:

</span>3Cu2+ + 2(AsO4)3-<span> = Cu3(AsO4)2
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Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq)
IgorC [24]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:

NaHCO_3(aq.)+CH_3COOH(aq.)\rightarrow CH_3COONa(aq.)+H_2O(l)+CO_2(g)

Ionic form of the above equation follows:

Na^+(aq.)+HCO_3^-(aq.)+CH_3COO^-(aq.)+H^+(aq.)\rightarrow CH_3COO^-(aq.)+Na^+(aq.)+H_2O(l)+CO_2(g)

As, sodium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

HCO_3^-(aq.)+H^+(aq.)\rightarrow CO_2(g)+H_2O(l)

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8 0
3 years ago
How does the Theory of Plate Tectonics explain the location of same fossils at Points A and B?
Artemon [7]
Yellow because Pangea all the continents were together
5 0
3 years ago
Analysis of skunk spray yields a molecule with 44.77% c, 7.46% h and 47.76% s by mass. what is the empirical formula for this mo
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Suppose we have 100 gr of the substance. Then by weight, it would contain 44.77 gr of C, 7.46 gr of H and 47.76 gr of S. We need to look up the atomic weights of these atoms; M_H=1, M_C=12, M_S=32. The following formula holds (where n are the moles of the substance, M its molecular mass and m its mass): n=m/M. Substituting the known quantities for each element, we get that the substance has 3.73 moles of C, 7.46 moles of H and 1.49 moles of S. In the empirical formula for the molecule, all atoms appear an integer amout of times. Hence, for every mole of Sulfur, we have 2.5 moles of C and 5 moles of H (by taking the moles ratios). Thus, for every 2 moles of sulfur, we have 5 moles of C and 10 moles of H. Now that all the coefficients are integer, we have arrived at an empirical formula for the skunk spray agent: C_5H_{10}S_2
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