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velikii [3]
2 years ago
7

If the heat of fusion of water is 80 cal/g, the amount of heat energy required to change 15.0 grams of ice at 0°C to

Chemistry
1 answer:
kicyunya [14]2 years ago
4 0

Answer:

1200 cal

Explanation:

80 cal/g * 15 g = 1200 cal

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