Answer: I think the answer is, 3.312177825e+24 atoms
Explanation: I had a problem similar to this, Hope this helps!
Answer:
Tc^(+7) - 2.35*10^-5M
PO4(^-3) - 5.50*10^-5M
Explanation:
Tc3(PO4)7 <---> 
1 mol 3 mol 7 mol
7.85 X 10^-6 M 3*7.85*10^-6M 7*7.85*10^-6M
2.35*10^-5M 5.50*10^-5M
Answer:
1. A
2. C
3. B
4. D
5. D
6. B
Explanation:
I'm not quiet sure on 5 but I'm pretty sure its correct
Answer:
41264 g of CO₂
Explanation:
Combustion reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.
In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.
We have the volume of propane but we need moles of it, so we need to apply density.
Density = mass / volume so mass = density . volume.
Density of propane is: 493 g/L
Mass of propane is 493 g/L . 27.9L = 13754.7 g
We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles
According to reaction, 1 mol of propane can produce 3 moles of CO₂
Our 312.6 moles will produce 312.6 . 3 = 937.8 moles
We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g
