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3 years ago

Please choose the correct sequence that describes the excitement of an atom.

Chemistry

1 answer:

Angelina_Jolie [31]3 years ago

7 0

Answer: A because it’s correct

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Thewood,papertowel,andaluminumfoilwereallatroomtemperaturewhenyou measured temperature for each object. Based on your results, e

Paraphin [41]

Answer:

The difference in the observed temperature of measurement of the material and their apparent temperature when touched by hand is due to their relative higher affinity for heat. As such aluminum with a lower heat capacity or higher affinity or transmission ability for heat than the hand will feel cool when touched.

The materials have different specific heat capacity or heat affinity which is a measure of their ability to quickly take on the temperature of their surroundings, in this case their ability to conduct heat energy relative to the hand

Explanation:

The aluminium with specific heat capacity of 0.900 J/gm K requires very little heat to cause a temperature change compared to a wood with a specific heat capacity of 1.76 J/gm K such that when one touches a piece of aluminium, the aluminium quickly raises its temperature by absorbing heat from the hand which is observed as it (the aluminium), being cold. The same can be said of the paper towel

The relationship is

Heat loss or gain = mass × specific heat capacity × temperature change

In other words, aluminium has a higher affinity for heat than either the hand or wood

5 0

3 years ago

Would someone mind helping me? I really need this answer but I'm so confused. I would appreciate any help :) and if you get the

Svetllana [295]

Answer:

Explanation:

liquids thake the shape of what holds them so shape is changing and volume is the same

7 0

3 years ago

Read 2 more answers

The solubility of agcl(s) in water at 25 ∘c is 1.33×10−5mol/l and its δh∘ of solution is 65.7 kj/mol. what is the solubility at

slamgirl [31]

According to this equation:

AgCl(s) ↔ Ag+(aq) + Cl-(aq)

so K1 = [Ag+][Cl-]

when [Ag+] = [Cl-] we can assume both = X

and when we have X the solubility = 1.33 x 10^-5 mol / L

by substitution:

∴ K1 = X^2

= (1.33 x 10^-5)^2

= 1.77 x 10^-10

by using vant's Hoff equation:

ln(K2/K1) = (ΔH/R)*(1/T2-1/T1)

when ΔH = 65700 J / mol

R = 8.314

T1 = 25+273 = 298 K

T2 = 47.7 +273 =320.7

by substitution:

∴㏑(K2/1.77 x 10^-10) = (65700/8.314) * ( 1/320.7 - 1/ 298)

by solving for K2

∴K2 = 2.7 x 10^-11

and when K2 = X^2

∴ the solubility X = √(2.7 x 10^-11)

= 5.2 x 10^-6 mol/L

8 0

3 years ago

It takes to break an carbon-chlorine single bond. Calculate the maximum wavelength of light for which an carbon-chlorine single

Maslowich

Answer:

It takes approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

The maximum wavelength of a photon that can break one such bond is approximately $3.66\times 10^{-7}\; \rm m$ (in vacuum.) That's the same as $3.66 \times 10^{2}\; \rm nm$ (rounded to three significant figures.)

Explanation:

<h3>Energy per bond</h3>

The standard bond enthalpy of $\rm C-Cl$ single bonds is approximately $\rm 327\; \rm kJ \cdot mol^{-1}$ (note that the exact value can varies across sources.) In other words, it would take approximately $327\; \rm kJ$ of energy to break one mole of these bonds.

The Avogadro Constant $N_A \approx 6.023\times 10^{23}\; \rm mol^{-1}$ gives the number of $\rm C-Cl$ bonds in one mole of these bonds. Based on these information, calculate the energy of one such bond:

$\begin{aligned}& E(\text{one $\mathrm{C-Cl}$ bond}) \\ &= \frac{E(\text{one mole of $\mathrm{C-Cl}$ bonds})}{N_A} = \frac{327\; \rm kJ\cdot mol^{-1}}{6.023\times 10^{23}\; \rm mol^{-1}} \\ &\approx 5.429\times 10^{-22}\; \rm kJ = 5.429\times 10^{-19}\; \rm J \end{aligned}$ .

Therefore, it would take approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

<h3>Minimum frequency and maximum wavelength </h3>

The Einstein-Planck Relation relates the frequency $f$ of a photon to its energy $E$ :

$E = h \cdot f$ .

The $h$ here represents the Planck Constant:

$h \approx 6.63 \times 10^{-34}\; \rm J \cdot s$ .

A photon that can break one $\rm C-Cl$ single bond should have more than $5.43\times 10^{-19}\; \rm J$ of energy. Apply the Einstein-Planck Relation to find the frequency of a photon with exactly that much energy:

$\begin{aligned}f &= \frac{E}{h}\\ &\approx \frac{5.43\times 10^{-19}\; \rm J}{6.63 \times 10^{-34}\; \rm J\cdot s} \\ &\approx 8.19 \times 10^{14}\; \rm s^{-1} = 8.19 \times 10^{14}\; \rm Hz\end{aligned}$ .

What would be the wavelength $\lambda$ of a photon with a frequency of approximately $8.19 \times 10^{14}\; \rm Hz$ ? The exact answer to that depends on the medium that this photon is travelling through. To be precise, the exact answer depends on the speed of light in that medium:

$\displaystyle \lambda = \frac{(\text{speed of light})}{f}$ .

In vacuum, the speed of light is $c \approx 2.998\times 10^{8}\; \rm m \cdot s^{-1}$ . Therefore, the wavelength of that $8.19 \times 10^{14}\; \rm Hz$ photon in vacuum would be:

$\begin{aligned} \lambda &= \frac{c}{f} \\ & \approx \frac{2.998\times 10^{8}\; \rm m \cdot s^{-1}}{8.19\times 10^{14}\; \rm s^{-1}} \\ &\approx 3.66 \times 10^{-7}\; \rm m = 3.66 \times 10^{2}\; \rm nm\end{aligned}$ .

(Side note: that wavelength corresponds to a photon in the ultraviolet region of the electromagnetic spectrum.)

7 0

3 years ago

an atom has 70 protons, 70 electrons, and 99 neutrons. what is the mass number? group of answer choices

Blizzard [7]

Answer:

169

Explanation:

protons+neutrons=atomic mass

70+99=169

6 0

3 years ago