To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
Answer:
it's 12 because
2×6=12
3×4=12
4×3=12
and all of them have twelve
Answer:
no can you help me
Step-by-step explanation:
Y-13=4(x-2)
y-13=4x-8
y=4x+5
When you're raising a power to a power, you multiply.
Since they are equal the exponent has to be the same.
2p=8; this is the equation we'll use to make sure we get the value of p. Let's divide.
8÷2=4=p
So, p=4.
