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Flauer [41]
3 years ago
11

Which of the following are examples of chemical changes? Select all that apply.

Chemistry
1 answer:
Travka [436]3 years ago
6 0

A B and C are all chemical changes. paper tearing is not.

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How do you complete an oxidation reaction? Organic chemistry
alexira [117]
From Organic Chemistry point of view, Oxidation is defined as i) Removal of Hydrogen or ii) Addition of Oxygen.

Thiols fails to oxidize the way as Alcohols do, i.e. alcohols on oxidation yields aldehydes or Ketones, while Thiols does not. Following are two reactions showing oxidation of Thiol (compound given in question), in first reaction Thiol is converted to Sulfonic Acid with treatment with Nitric acid or KMnO₄. In second reaction Thiol is oxidized to disulfide when reacted with mild oxidizing agent I₂ in basic condition.

5 0
3 years ago
One mole of nitrogen dioxide has 6.02 x 10²³ nitrogen dioxide molecules. If nitrogen dioxide is made of one nitrogen atom and tw
marta [7]

Your answer, IMHO, is correct.

The detailed work is below:

1) to calculate the mass of one mole of nitrogen dioxide (NO₂): 14+2*16=46 (gr/mole);

it means, the mass of 1 mole of NO₂ is 46 gramms. Then

2) to calculate the space in milliliteres: V=mass/density=46/1.5=30.(6) (millilitres)≈31 ml.

3 0
4 years ago
Read 2 more answers
What is the volume of 8.50 moles of hydrogen gas?
Cerrena [4.2K]
Okay! 
8.50molH, represents 8.50 moles of Hydrogen gas!

To convert from moles to volume multiply it by the ratio of L/molH
mol of anything in a conversion problem is always 1 unless you are going to an unknown! Try to memorize this, but the number you always put in for the # of liters in a conversion problem is 22.4L (L is a measure of volume) 

8.50molH * (22.4 L/ 1 molH)

190.L of Hydrogen Gas. 

Hope that helped!
3 0
4 years ago
Can someone please help
Zina [86]
Electrical to thermal
4 0
3 years ago
Read 2 more answers
How many moles of koh are required to prepare 0.80 l of 6.4 m koh? 0.13 mol koh 5.1 mol koh 7.2 mol koh 8.0 mol koh?
wel
Answer is: 5,1 mol KOH.
V (KOH) = 0,8l = 0,8 dm³. 
c (KOH) = 6,4 mol/dm³.
V - volume of solution.
c - concentration of solution.
c = n÷V
n - amount of substance.
n (KOH) = c·V = 6,4 mol/dm³ · 0,8 dm³ = 5,12 mol.
Potassium hydroxide (KOH) can<span> </span>dissolve<span> in water at room temperature.</span>


8 0
4 years ago
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