From Organic Chemistry point of view, Oxidation is defined as i)
Removal of Hydrogen or ii)
Addition of Oxygen.
Thiols fails to oxidize the way as Alcohols do, i.e. alcohols on oxidation yields aldehydes or Ketones, while Thiols does not. Following are two reactions showing oxidation of Thiol (compound given in question), in first reaction Thiol is converted to
Sulfonic Acid with treatment with Nitric acid or KMnO₄. In second reaction Thiol is oxidized to
disulfide when reacted with mild oxidizing agent I₂ in basic condition.
Your answer, IMHO, is correct.
The detailed work is below:
1) to calculate the mass of one mole of nitrogen dioxide (NO₂): 14+2*16=46 (gr/mole);
it means, the mass of 1 mole of NO₂ is 46 gramms. Then
2) to calculate the space in milliliteres: V=mass/density=46/1.5=30.(6) (millilitres)≈31 ml.
Okay!
8.50molH, represents 8.50 moles of Hydrogen gas!
To convert from moles to volume multiply it by the ratio of L/molH
mol of anything in a conversion problem is always 1 unless you are going to an unknown! Try to memorize this, but the number you always put in for the # of liters in a conversion problem is 22.4L (L is a measure of volume)
8.50molH * (22.4 L/ 1 molH)
190.L of Hydrogen Gas.
Hope that helped!
Answer is: 5,1 mol KOH.
V (KOH) = 0,8l = 0,8 dm³.
c (KOH) = 6,4 mol/dm³.
V - volume of solution.
c - concentration of solution.
c = n÷V
n - amount of substance.
n (KOH) = c·V = 6,4 mol/dm³ · 0,8 dm³ = 5,12 mol.
Potassium hydroxide (KOH) can<span> </span>dissolve<span> in water at room temperature.</span>