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miskamm [114]
2 years ago
15

Sodium chloride, an ionic compound, has a high melting point whereas paraffin wax, a molecular compound, melts easily.Explain wh

y.
Chemistry
1 answer:
taurus [48]2 years ago
4 0

Answer:

NaCl is ionic so has strong ionic bonds between ions; paraffin is molecular and has weak intermolecular forces between molecules

Explanation:

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AUG, the codon that codes for the amino acid methionine is also called a ____ codon (answer choices 1.start 2.Stop 3.Go 4.beginn
Katarina [22]
<h2>Answer:  START (2)</h2>

Explanation:

AUG is a <u>START</u> codon.  (2)

A start codon is the first codon translated by a ribosome. It usually produces an amino acid that initiates the producyion of a polypeptide chain.

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3 years ago
How do waves interact with matter ?
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6 0
3 years ago
Due Tuesday 09-07-2021 Please help immediately!! I have 10 missing assignments from being absent
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7 0
2 years ago
Read 2 more answers
How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points
OLga [1]

The heat lost is -7.32*10^-^5J

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

Q = mc(\delta)T

  • Q = Heat Transfer
  • m = mass = 1277g
  • ΔT  = change in temperature

\delta T = (400 - 273) - (263 - 273) = \\&#10;\delta T = T_2 - T_1\\&#10;\delta T = -10 - 127\\&#10;\delta T = -137^0C

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

Q = mc\delta T\\&#10;Q = 1277 * 4.186 * -137\\&#10;Q = -732336.514J

The heat loss is approximately -7.32*10^-^5J

Learn more on heat transfer here;

brainly.com/question/16055406

6 0
2 years ago
!!!Need answer for chem homework ASAP PLS !!!!
stealth61 [152]

Answer:

The answer to your question is: kc = 6.48

Explanation:

Data

             Given                 Molecular weight

CaO =    44.6 g                    56 g

CO₂ =     26 g                       44 g

CaCO₃ = 42.3 g                  100 g

Find moles

        CaO                 56 g ----------------  1 mol

                                 44.6 g --------------   x

                               x = (44.6 x 1) / 56 = 0.8 mol

        CO₂                 44 g -----------------  1 mol

                                26 g ----------------    x

                               x = (26 x 1 ) / 44 = 0.6  moles

        CaCO₃            100 g ---------------   1 mol

                                42.3g --------------    x

                              x = (42.3 x 1) / 100 = 0.423 moles

       

Concentrations

 

        CaO     =    0.8 / 6.5  = 0.12 M

         CO₂    =     0.6 / 6.5 = 0.09 M

        CaCO₃  =   0.423 / 6.5 = 0.07 M

Equilibrium constant =   \frac{[products]}{[reactants]}

Kc = [0.07] / [[0.12][0.09]

Kc = 0.07 / 0.0108

kc = 6.48

7 0
3 years ago
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