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gtnhenbr [62]
4 years ago
8

When an athlete gets hurt they apply sometimes an instant cold pack to the injury. the instant cold pack works by mixing two che

micals that create a chemical reaction. what evidence is there that a chemical reaction is taking place in the cold pack?
a. change in odor
b. change in color
c. formation of gas
d. temperature change
Chemistry
2 answers:
siniylev [52]4 years ago
8 0
The answer would be D
trasher [3.6K]4 years ago
4 0

yes of course the answer is D, temperature change.

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A balloon is inflated with helium to a volume of 45L at room temperature (298K). If the balloon is cooled to 200.K, what is the
igor_vitrenko [27]

Answer:

V₂ = 30.20 L

Explanation:

Given data:

Initial volume = 45 L

Initial temperature = 298 K

Final temperature = 200 K

Final volume = ?

Solution;

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 45 L × 200 K / 298 k

V₂ = 9000 L.K / 298 K

V₂ = 30.20 L

8 0
3 years ago
Using these metal ion/metal standard reduction potentials calculate cell potential for Cu2+(aq) + Cd(s) →Cd2+(aq)+ Cu(s) Cu2+(aq
Katena32 [7]

Solution :

Cd(s) ---------------------->  Cd^{+2} (aq) + 2e^-      ,     E_0  =   0.34 v

Cu^{+2}  (aq)  +   2e^-  ------------> Cu (s)             ,     E_0  =  -0.04 v

----------------------------------------------------------------------------------------------

Cd(s)  +  Cu^{+2}  (aq)  ------------->  Cd^{+2} (aq)  +  Cu (s)   ,      E_0  =  0.30 v  

The cell potential is defined as the measure of \text{ potential difference }  between the \text{two half cells} of an electrochemical cell.  

4 0
3 years ago
Marie Curie named polonium in honor of Poland. 1. True or 2. False
natali 33 [55]
<span>Radium and Polonium were named in honor of Marie Curie.
SO yeh true
Hope this helps!
:)
</span>
7 0
3 years ago
Calculate the equilibrium concentration of H 3 O H3O in a 0.20 M M solution of oxalic acid. Express your answer to two significa
Black_prince [1.1K]

<u>Answer:</u> The equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

<u>Explanation:</u>

We are given:

Molarity of oxalic acid solution = 0.20 M

Oxalic acid (H_2C_2O_4) is a weak acid and will dissociate 2 hydrogen ions.

  • The chemical equation for the first dissociation of oxalic acid follows:

               H_2C_2O_4(aq.)+H_2O\rightleftharpoons H_3O^+(aq.)+HC_2O_4^-(aq.)

<u>Initial:</u>        0.20

<u>At eqllm:</u>    0.20-x                            x                 x

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H_3O^+][HC_2O_4^{-}]}{[H_2C_2O_4]}

We know that:

Ka_1\text{ for }H_2C_2O_4=0.059

Putting values in above equation, we get:

0.059=\frac{x\times x}{(0.20-x)}\\\\x=-0.142,0.083

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = x = 0.083 M

  • The chemical equation for the second dissociation of oxalic acid:

                 HC_2O_4^-(aq.)+H_2O\rightarrow H_3O^+(aq.)+C_2O_4^{2-}(aq.)

<u>Initial:</u>         0.083  

<u>At eqllm:</u>    0.083-y                      0.083+y               y

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H_3O^+][C_2O_4^{2-}]}{[HC_2O_4^-]}

We know that:

Ka_2\text{ for }H_2C_2O_4=6.4\times 10^{-5}

Putting values in above equation, we get:

6.4\times 10^{-5}=\frac{(0.083+y)\times y}{(0.083-y)}\\\\y=-0.083,0.0000639

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = y = 0.0000639 M

Total concentration of hydronium ion = [x + y] = [0.083 + 0.0000639] = 0.0830639 M

Hence, the equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

7 0
3 years ago
Which atom in each pair has the larger atomic radius?
nikitadnepr [17]

Answer:

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

8. Gold, Au.

Explanation:

Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

Additionally, the unit of measurement of the atomic radius of chemical elements is picometers (1 pm = 10 - 12 m).

1. Li or K: the atomic radius of lithium is 167 pm while that of potassium is 243 pm.

2. Ca or Ni: the atomic radius of calcium is 194 pm while that of nickel is 149 pm.

3. Ga or B: the atomic radius of gallium is 136 pm while that of boron is 87 pm.

4. O or C: the atomic radius of oxygen is 48 pm while that of carbon is 67 pm.

5. Cl or Br: the atomic radius of chlorine is 79 pm while that of bromine is 94 pm.

6. Be or Ba: the atomic radius of berryllium is 112 pm while that of barium is 253 pm.

7. Si or S: the atomic radius of silicon is 111 pm while that of sulphur is 88 pm.

8. Fe or Au: the atomic radius of iron is 156 pm while that of gold is 174 pm.

7 0
3 years ago
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