If two people have sex in certain positions then pregnancy is not possible because of gravity

Why stone is not a combustable and insolouble in water

zaharov [31]

Answer:

Stone does not have organic matter in it to burn in presence of air. Hence, it is a non combustible.

Rocks are quite bundled up together. Hence, they are very difficult to get mixed together.

4 0

3 years ago

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If a plant produces 9.31 mol of C6H12O6, how many moles of H2O are needed?

Mashutka [201]

The complete balanced chemical equation for photosynthesis in plants is:

6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Based on the balanced equation the molar ratio between H₂O and C₆H₁₂O₆ is 6:1

This means that 6 moles of H₂O is need for every 1 mole of C₆H₁₂O₆

9.31 mol of C₆H₁₂O₆ x (6 moles of H₂O / 1 mole of C₆H₁₂O₆) = 55.86 moles of H₂O

Thus the moles of H₂O need is 55.86 .

5 0

3 years ago

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What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not

Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] -Where A⁻ is acetate ion and HA is acetic acid-

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

1,7378 = [A⁻]/[HA] (1)

As concentration of buffer is 0,15M, it is possible to write:

[A⁻] + [HA] = 0,15M (2)

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need acetic acid 0,055M and acetate 0,095M to obtain the buffer you need.

i hope it helps!

7 0

3 years ago

Which formula contains two non- metals? BaO NaBr KI Si O2

Yakvenalex [24]

SiO2 is the only possible choice because the other formulas contain metals. how do we know this? because the other formulas contain elements located on the left of the “staircase” on the periodic table that separates metals from non-metals.

6 0

3 years ago

If 3.3167 moles of Al are produced, how many moles of AlCl3 were reacted? I

tresset_1 [31]

Answer:

3.3167 moles Of AlCl3

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3Ca + 2AlCl3 —> 3CaCl2 + 2Al

From the balanced equation above,

2 moles of AlCl3 reacted to produce 2 moles of Al.

Finally, we shall obtained the number of moles of AlCl3 that reacted to produce 3.3167 moles of Al as follow:

From the balanced equation above,

2 moles of AlCl3 reacted to produce 2 moles of Al.

Therefore, 3.3167 moles Of AlCl3 will also react to produce 3.3167 moles of Al.

Thus, 3.3167 moles Of AlCl3 is needed for the reaction.

8 0

3 years ago