<u>Given:</u>
Volume of 0.9% NaCl = 500 ml
Time (t) = 4 hrs
<u>To determine:</u>
The infusion rate of NaCl in ml/hr
<u>Explanation:</u>
Based on the information- 500 ml of NaCl is to be given over a time span of 4 hrs
Hence, the volume of NaCl to be administered per hr is:-
= 1 hr * 500 ml/4 hr = 125 ml
Ans: Infusion rate = 125 ml/hr
Answer:
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Explanation:
Step 1: Data given
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L
Temperature = 198 °C = 471 K
The volume will be reduced to 2.50 L
Step 2 Calculate the new temperature via Charles' law
V1/T2 = V2/T2
⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L
⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K
⇒with V2 = the reduced volume of the gas = 2.50 L
⇒with T2 = the new temperature = TO BE DETERMINED
5.10 L / 471 K = 2.50 L / T2
T2 = 2.50 L / (5.10 L / 471 K)
T2 = 230.9 K = -42.1
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Answer:
increase in temperature of the intrinsic semiconductor
Explanation:
- If the p-side has a higher doping concentration, it implies that number of holes (positive ion) increased which is greater than number of electron (negative ion) in the n-side
- in order to balance the intrinsic concentration, that is to balance the number of holes and electrons which depends on temperature.
- an increase in the temperature of the intrinsic semiconductor (p-side), increases the number of electron but number of holes remains constant.
A balance in the intrinsic concentration helps in tuning to the same radio channel.
A reducing agent is one which is oxidised in the reaction itself. When you take into account the oxidation numbers you will see that the Cl- ions are oxidised from an oxidation number of -1 to 0 in Cl2. Therefore Cl- ions are the reducing agent.
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