If two people have sex in certain positions then pregnancy is not possible because of gravity

The strongly polar, hydrogen-bonding properties of water make it an excellent solvent for ionic (charged) species. By contrast,

trapecia [35]

Answer:

hello your question is incomplete attached below is the complete question

Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

Explanation:

Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

attached below is the remaining part of the solution

7 0

4 years ago

A 24% acid solution is mixed with a 14% acid solution to form a 19% acid solution. How many liters of the 24% acid solution are

Kay [80]

Answer: 5 Liters

Explanation:

According to the dilution law,

$M_1V_1+M_2V_2=M_3V_3$

where,

$M_1$ = concentration of first solution = 24%

$V_1$ = volume of first solution = x L

$M_2$ = concentration of second solution = 14%

$V_2$ = volume of second solution = (10-x) L

$M_3$ = concentration of final solution = 19%

$V_2$ = volume of final solution = 10 L

Putting i the values, we get:

$24\times x+14\times (10-x)=19\times 10$

$x=5L$

Therefore, 5 Liters of the 24% acid solution are used to make 10 liters of the 19% acid solution.

4 0

4 years ago

Calculate the total energy, in kilojoules, that is needed to turn a 46 g block

gogolik [260]

Answer: The amount of heat absorbed is 141.004 kJ.

Explanation:

In order to calculate the amount of heat released while converting given amount of steam (gaseous state) to ice (solid state), few processes are involved:

(1): $H_2O (s) (-25^oC, 248K) \rightleftharpoons H_2O(s) (0^oC,273K)$

(2): $H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)$

(3): $H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)$

(4): $H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)$

Calculating the heat absorbed for the process having the same temperature:

$q=m\times \Delta H_{(f , v)}$ ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and $\Delta H_{(f , v)}$ is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

$q=m\times C_{s,l}\times (T_2-T_1)$ ......(ii)

where,

$C_{s,l}$ = specific heat of solid or liquid

$T_2\text{ and }T_1$ are final and initial temperatures respectively

For process 1:

We are given:

$m=46g\\C=2.108J/g^oC\\T_2=0^oC\\T_1=-25^oC$

Putting values in equation (i), we get:

$q_1=46g\times 2.108J/g^oC\times (0-(-25))\\\\q_1=2424.2J$

For process 2:

We are given:

$m=46g\\\Delta H_{fusion}=334J/g$

Putting values in equation (i), we get:

$q_2=46g\times 334J/g\\\\q_2=15364J$

For process 3:

We are given:

$m=46g\\C=4.186J/g^oC\\T_2=100^oC\\T_1=0^oC$

Putting values in equation (i), we get:

$q_3=46g\times 4.186J/g^oC\times (100-0)\\\\q_3=19255.6J$

For process 4:

We are given:

$m=46g\\\Delta H_{vap}=2260J/g$

Putting values in equation (i), we get:

$q_4=46g\times 2260J/g\\\\q_4=103960J$

Calculating the total amount of heat released:

$Q=q_1+q_2+q_3+q_4$

$Q=[(2424.2)+(15364)+(19255.6)+(103960)]$

$Q=141003.8J=141.004kJ$ (Conversion factor: 1 kJ = 1000J)

Hence, the amount of heat absorbed is 141.004 kJ.

7 0

3 years ago

What are thermal plasmas?

vitfil [10]

plasmas that reach a temperature equal to their surroundings

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6 0

3 years ago

Read 2 more answers

If a mineral breaks into cubes when struck with a rock hammer whats being measured

emmainna [20.7K]

When struck, the mineral is tested for lattice type. Depending on how it shatters, scientists can determine how the mineral forms on the atomic level by noting the molecular weaknesses of the system. These weaknesses are the points at which the mineral breaks along.

Depending on the type of hammer, they could also be testing the tensile strength and, even possibly, the hardness, depending on the angle of the blow. How hard the rock can be hit without breaking is the TS, and whether or not the mineral is scratched by the hammer is the hardness.

4 0

3 years ago