Answer:
108ft^2
Step-by-step explanation:
since you going up in value, you mulitple 3*9 to get 27. that means you have to multiple the other value of the bigger rectangle by 2. therefore 6*18=108
Slope:y2-y1/x2-x1
-1-4/4-(-3)
-5/4+3
-5/7
1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
x = 9
Step-by-step explanation:
set a proportion: 8/12 = 6/x => 8x = 72 => x = 9
Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl

Radius is half of diameter.
<u>Given</u> -
<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>
Putting the known values into the formula to get the value of the volume of bowl :

= 3.48888cm³
= 3.48cm³