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antiseptic1488 [7]
3 years ago
8

On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city

mentioned in part a. Vertical soundings reveal an environmental lapse rate of 6.5°C per kilometer and indicate that the tropopause is encountered at 16 km. What is the air temperature at the tropopause?
Physics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

The air temperature at the tropopause is - 79 °C

Explanation:

We know that a station near the equator has a surface temperature of 25°C

Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.

The tropopause is encountered at 16 km.

In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.

This linear function will have the following structure :

f(x)=ax+b

Where ''a'' and ''b'' are real numbers.

Let's write T(x) to denote the temperature '' T '' in function of the distance

'' x '' ⇒

T(x)=ax+b

We can reorder the function as :

T(x)=b+ax (I)

Now, at the surface the value of ''x'' is 0 km and the temperature is 25°C so in the function (I) we write :

T(0)=25=b+a(0) ⇒ b=25 ⇒

T(x)=25+ax (II)

In (II) the value of ''a'' represents the change in temperature per kilometer.

Because the temperature decrease with the height this number will be negative and also a data from the question ⇒

T(x)=25-(6.5)x (III)

In (III) we deduced the linear equation. The last step is to replace by x=16 in (III) ⇒

T(16)=25-(6.5)(16)=-79

The air temperature at the tropopause is - 79 °C

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Answer:

a) time taken to catch up with speeding car is 12.25 secs

b) the police car will travel 273.8 m to catch up with the speeding car

Explanation:

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acceleration of police car = 10 mi/hr = 4.47 m/s²

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we substitute

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t = 7 + 5.25

t = 12.25 secs

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distance = 109.5 + 164.3

distance = 273.8 m

Therefore, the police car will travel 273.8 m to catch up with the speeding car

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