Answer:
6844.5 m/s.
Explanation:
To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.
Formula for centripetal force is;
F_c = mv²/r
Formula for gravitational force is:
F_g = GmM/r²
Thus;
mv²/r = GmM/r²
m is the mass of the satellite and M is mass of the earth.
Making v the subject, we have;
v = √(GM/r)
We are given;
G = 6.67 × 10^(-11) m/kg²
M = 5.97 × 10^(24) kg
r = 8500 km = 8500000
Thus;
v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.
Answer:
A.) V = 14 m/s
B.) h = 36.6 m
Explanation:
Given the formula v = √2gh
where g = 9.8m/sec^2 is the acceleration due to gravity.
A.) Determine the impact velocity for an object dropped from a height of 10 m.
Substitute height h in the given formula
V = √2gh
V = √2 × 9.8 × 10
V = √196
V = 14 m/s
b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.
Substitute the velocity in the given formula and make height h the subject of formula.
26.8 = √2 × 9.8 × h
Square both sides
718.24 = 19.6h
h = 718.24 / 19.6
h = 36.64 m
h = 36.6 m
<h2>
Velocity of 0.2 kg ball is 0.17 m/s</h2>
Explanation:
Let the mass of balls be m and M.
Initial velocity ball 1 be u₁, ball 2 be u₂
Final velocity ball 1 be v₁, ball 2 be v₂
Initial momentum = m x u₁ + M x u₂ = 0.2 x 0.3 + 0.1 x 0.1 = 0.07 kgm/s
Final momentum = m x v₁ + M x v₂ = 0.2 x v₁ + 0.1 x 0.36 = 0.2v₁ + 0.036
We have momentum conservation
Initial momentum = Final momentum
0.07 = 0.2v₁ + 0.036
v₁ = 0.17 m/s
Velocity of 0.2 kg ball is 0.17 m/s
Answer:
480.2 m
Explanation:
The following data were obtained from the question:
Speed of sound (v) = 343 m/s.
Time (t) = 2.8 s
Distance (x) of the cliff =?
The distance of the cliff from the woman can be obtained as follow:
v = 2x /t
343 = 2x /2.8
Cross multiply
2x = 343 × 2.8
2x = 960.4
Divide both side by the coefficient of x i.e 2
x = 960.4/2
x = 480.2 m
Therefore, the cliff is 480.2 m away from the woman.
Answer: 0.55m
1. First find Vf
• 4 Sin(10)=0.7
•Vf= 0.7
2. Find time
•9.8=0.7/t
•9.8t=0.7
•t=0.07
3. Find distance
• 4 Cos(10)=d/0.14 < ————- double time
• d=0.55m
