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vesna_86 [32]
3 years ago
13

A. Starting with 1s2draw out the complete electron configuration for the most stable ionof selenium.

Chemistry
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

smskksdiskjssjsjdjdjjddjdjjddjjdejrjejie

You might be interested in
What does a molecule of a substance that is made up if three elements look like​
nasty-shy [4]

Answer:

Whether something is a molecule or not depends on the type of bond that is formed when its atoms join together. In general, electrons can be shared between atoms (a molecular bond) or electrons can be completely removed from one atom and given to another (an ionic bond). Molecules have molecular bonds.

Explanation:

8 0
2 years ago
Periodic table the first row of elements fits in the period blank after the element blank the second row of elements fits in per
Bezzdna [24]

Answer:

The first row fits in period 2

The second row fits in period 3

Explanation:

Elements arranged vertically in the periodic table in groups that share similar chemical properties.

Elements are also organized horizontally in rows or periods

The length of each period is determined by the number of electrons that can occupy the sublevels being filled in that period.

7 0
3 years ago
A molecule contains four bonded pairs of electrons and zero lone pairs. What is the name of the molecular geometry?
vagabundo [1.1K]

Answer: Option (d) is the correct answer.

Explanation:

A tetarhedral geometry is the geometry which includes four atoms bonded to the central atom and it does not contain any lone pair of electron.

For example,  CH_{4} has tetrahedral geometry.

Thus, we can conclude that a molecule which contains four bonded pairs of electrons and zero lone pairs. The name of the molecular geometry is tetrahedral.

4 0
3 years ago
A sample of oxygen occupies 20.1 liters under a pressure of 1520 torr at 25.0o What volume would it occupy at 25.0oC if the pres
Zolol [24]

Answer:

The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L

Explanation:

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant, so that the pressure of a gas in a closed container is inversely proportional to the volume of the container. That is, if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Considering an initial state 1 and a final state 2, it is true:

P1* V1= P2*V2

In this case:

  • P1= 20.1 L
  • V1= 1520 torr
  • P2= 760 torr
  • V2= ?

Replacing:

20.1 L* 1520 torr= 760 torr* V2

Solving:

V2=\frac{20.1 L* 1520 torr}{760 torr}

V2= 40.2 L

<em><u>The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L</u></em>

<em><u></u></em>

4 0
3 years ago
A 2.00-mol sample of hydrogen gas is heated at constant pressure from 294 K to 414 K. (a) Calculate the energy transferred to th
Furkat [3]

Answer:

a) The energy transferred is 6.91 kJ

b) The internal energy is 4.90 kJ

c) The work done on the gas is - 2.01 kJ

Explanation:

Step 1: Data given

Number of moles of hydrogen gas = 2.00 moles

Pressure = constant

Temperature is heated from 294 K to 414 K

Molar heat capacity of hydrogen gas = 28.8 J/mol*K

Step 2: Calculate the energy transferred to the gas by heat.

Q = n* Cp * ΔT

⇒with Q =the energy transferred

⇒with n = the number of moles = 2.00 moles

⇒with Cp = the Molar heat capacity of hydrogen gas = 28.8 J/mol*K

⇒ with ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

Q = 2.00 * 28.8 * 120

Q = 6912 J = 6.91 kJ

Step 3: Calculate the increase in its internal energy.

ΔEint = n*Cv*ΔT

⇒with ΔEint = the increase in its internal energy.

⇒with n = the number of moles = 2.00 moles

⇒with Cv = The constant volume = 20.4 J/mol*K

⇒with  ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

ΔEint = 2.00 * 20.4 * 120

ΔEint =4896 J = 4.90 kJ

Step 4: Calculate the work done on the gas.

Work done on the gas = -Q + ΔEint

W = -6.91 kJ + 4.90 kJ

W = -2.01 kJ

6 0
3 years ago
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