Neutralization reactions can be used in a laboratory setting in order t<span>o dispose of chemicals. When spills happens, for instance an acid is on the floor, you can use a base to neutralize the spill. Hope this answers the question. Have a nice day.</span>
<span>Answer:
2 C8H18 + 25 O2 => 16 CO2 + 18 H2O
1.0 kg = 1000 g C8H18 = 1000 g / 114.2293 g/mole = 8.75 moles C8H18
8.75 moles C8H18 produce (16/2) (8.75) = 70 moles CO2
70 moles CO2 = (70 moles) (44.0096 g/mole) = 3081 g CO2 = 3.1 kg CO2</span>
Answer:
initial temperature=
Explanation:
Assuming that the given follows the ideal gas nature;
mole of gass will remain same at any emperature:
putting all the value we get:
initial temperature=
Answer:
Mass = 64 g
Explanation:
Given data:
Mass of water produced = 36 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
CH₄ + 2O₂ CO₂ + 2H₂O
Number of moles of water produced:
Number of moles = mass/molar mass
Number of moles = 36 g/ 18 g/mol
Number of moles = 2 mol
Now we will compare the moles of water and oxygen.
H₂O : O₂
2 : 2
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 2 mol × 32 g/mol
Mass = 64 g
Mg2+ is the positive ion of the neutral atom Mg. This means that the neutral atom Mg lost the two excess electrons in its outermost energy level and became a positive ion with the two excess positive charges. To become neutral again, the Mg2+ ion has to regain two electrons again to balance the negative charge with the excess two positive charges.
