Complete Question in order
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Answer and Explanation:
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6.
A. 1575 - 1265 = 310J
B. KE 1/2 MV^2
V=√2·KE/M = √2(310)/12 V = 7.2mls
C. PE = 1265 = mgh
h= 1265/mg = 1265/(12)(92) h= 10.8m
7.
A. KE = 1/2 mv^2 0.5(5)(12)^2 KE = 360J
B. PE = mgh = (5)(9.8)(2.6) PE = 127.4J
C. ME = KE + PE = 360 + 127.4 ME = 487.4J
Answer:
The linear velocity of the racquet at the point of contact with the ball is 6 m/s.
Explanation:
Given;
angular velocity of the racquet, ω = 12 rad/s
distance of strike, r = 0.5 m
The linear velocity of the racquet at the point of contact is given by;
V = ωr
V = (12)(0.5)
V = 6 m/s
Therefore, linear velocity of the racquet at the point of contact with the ball is 6 m/s.
