Sorry, I most likely did this wrong; but hopefully I didn't!
HgO2
Na+H2CI
K2CI2
C2H6O2--> H2CO2
C5H12O2--> H2CO3
Given that,
Mass = 2 kg
Height = 10 m
Speed = 1 m/s
We need to calculate the initial energy
Using formula of potential energy
We need to calculate the final energy
Using formula of kinetic energy
Put the value into the formula
We need to calculate the velocity when it is traveling 3 meters
Using conservation of energy
Put the value into the formula
Hence, The initial and final energy are 196 J and 1 J.
The speed of the particle is 7.76 m/s.
Answer:
W = 85.73 m
Explanation:
given,
surveyor walks = 118 m
makes an angle of = 36.0° with the tree
to find the width of the river
W = 85.73 m
hence, the width of the river is equal to W = 85.73 m
<em>≈ 0.47 m/s²</em>
<em>Hi there !</em>
<em>Acceleration formula</em>
<em>a = (v₂ - v₁)/t</em>
<em />
<em>a = (26.8m/s - 24.8m/s)/4.3s</em>
<em>= (2m/s)/4.3s</em>
<em>≈ 0.47 m/s²</em>
<em>Good luck !</em>