Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m
Answer:
Part a)
Mass of m2 is given as
Part b)
Angular acceleration is given as
Part c)
Tension in the rope is given as
Explanation:
Part a)
When m1 and m2 both connected to the cylinder then the system is at rest
so we can use torque balance here
Part b)
When block m_2 is removed then system becomes unstable
so force equation of mass m1
also we have
now we have
so angular acceleration is given as
Part c)
Tension in the rope is given as
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