Sodium hypochlorite chemical name would be NaOCl. Then, the molecular weight should be:23 + 16 + 35.5 = <span>74.5 g/mole
Molarity unit is mole of molecule divided by 1000ml of solvent, in this case water. Then for 32.4g of molecule with 499ml solvent it would be:
32.4g / (74.5g/mole) / (1000ml/499ml)= 0.87 m</span>
Answer:
mgh
Explanation:
mass×acceleration due to gravity ×height
Answer:
H20
Explanation:
H20 (WATER) is a compound because its constituent atoms, oxygen and hydrogen are present in a definite ratio (1:2)
Answer:
There are <span>1.479×<span>10<span>−13</span></span></span> concentration of hydrogen ions <span>mo<span>lL</span></span>.
Explanation:
Because pH is a logarthmic scale, we can use the formula: <span><span>[<span>H+</span>]</span>=<span>10-pH</span></span>. Where...
=> <span>[<span>H+</span>]</span> is the concentration of hydrogen ions in the solution.
=> <span>pH</span> is the pH of the solution.
=> Where 10 is the base of the power - it's a logarithm formula.
We can now just sub in the values and solve for [<span><span>H+</span>]</span>.
<span><span><span>[<span>H+</span>]</span>=<span>10-pH</span></span><span><span>=<span>10<span>−<span>(12.83)</span></span></span></span><span>=1.479108388×<span>10<span>−13</span></span></span></span></span>
We can round (if required) to <span>1.479×<span>10<span>−13</span></span></span>.
Thus, there are <span>1.479×<span>10<span>−13</span></span></span> concentration of hydrogen ions <span><span>mol</span>L</span>.
Hope this helps :)
Answer:
A) The Al(s)
B) The Ni2+(aq)
C) The Cu2+
D) The Zn(s)
Explanation:
A) The Al(s) is the species that is being oxidized given that it is the one with the highest oxidation potential in the solution.
B) The Ni2+(aq) is the species that is being reduced given that it is the one with the highest reduction potential in the beaker.
C) The oxidizing agent is the substance that is being reduced or you can say the one that has the potential to oxidite other substance. In this case the agent is Cu2+ given that it reduces itself while oxidates the lead.
D) The metal added needs to have a reduction potential lower than the H+ in order to form the gas. The only listed that meets the requirement is the Zn(s).