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liubo4ka [24]
3 years ago
13

Calculate the number of atoms of each element and the total number of atoms contained in 2.50 moles of Al2(SO4)3.

Chemistry
1 answer:
Leokris [45]3 years ago
3 0

Answer:

15.05 * 10^23 atoms are present in 2.50moles of Al2(SO4)3

Explanation:

To solve this question, the Avogadro equation is used.

Number of moles (n) = number of atoms (N) / Avogadro number.

n = N / 6.02*10^23

So therefore;

2.50moles = N / 6.02* 10^23

N = 6.02* 10^23 * 2.50

N = 15.05* 10^23 atoms.

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The complete question is shown in the image attached.

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