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dybincka [34]
2 years ago
9

The fraction 6/10 is equivalent to which of the following? 12/24 or 24/40 or 3/6 or 16/20

Mathematics
2 answers:
VARVARA [1.3K]2 years ago
6 0

Answer:

24/40

Step-by-step explanation:

You can multiply both the numerator and denominator by any number

Option #3: Lets multiply by 1/2 since when you multiply 6*1/2 it equals 3 and that is the same numerator as option #3 and so now let's do the same again to the denominator 10*1/2 equals 5 and that is NOT equal to 6 in the denominator for option #3 and you can't get 3 any other way than multiplying by 1/2 (same as *.5) and so it is wrong.

Now since we know how to do it I'll just do the math for the rest.

Option 1:

6/10

6*2/10*2

12/20 and that doesn't match so it's wrong.

Option 2:

6/10

6*4/10*4

=

24/40

It matches so it's correct let's try option 4 just to check.

Option 4:

6/10

6*2/10*2

12/20

that doesn't match so it's wrong (you could have tried multiplying by decimals by I doubt you are there to that kind of math yet.)

Answer: 24/40

Amanda [17]2 years ago
3 0

Answer:

It is equivalent to 24/40

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3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
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