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Ganezh [65]
3 years ago
15

What is 7/8 + 1/2 on a ruler

Engineering
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer:

11/8

Explanation:

7/8+4/8=11/8 if you want it on a ruler you need to go online and type fraction to decimal converter and put in 11/8 into a decimal

svp [43]3 years ago
3 0
11/8 or 1.375 as a decimal
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A keyboard, monitor and mouse are all considered as computer hardware and a program is known as a software.
Iteru [2.4K]

Answer:

This should be true because program is a software and mouse and keyboard are specific computer hardware to make your exsperience with a computer more efficent and faster.

5 0
3 years ago
Alternating current flows in___ direction(s) and direct current flows in___direction(s)
Oduvanchick [21]

Answer:

<u><em>both, one</em></u>

Explanation:

<em>Alternating current flows in both directions and direct current flows in one  direction.</em>

<em></em>

<em>Hope it helps.</em>

<em>;)</em>

<em><3</em>

8 0
3 years ago
You must signal _____ before any turn or lane change. A. 5 seconds B. 10 seconds C. 50 ft D. 100 ft
Nezavi [6.7K]
The answer is D! hope you pass
6 0
3 years ago
Read 2 more answers
How much calcium chloride will react with100mg of soda ash?
mixer [17]

Answer:

105mg of calcium chloride CaCl_{2}

Explanation:

The molecular formula of calcium chloride is CaCl_{2} and the molecular formula of soda ash is Na_{2}CO_{3}

First of all you should write the balanced reaction between both compounds, so:

CaCl_{2}+Na_{2}CO_{3}=2NaCl+CaCO_{3}

Then you should have the molar mass of the two compounds:

Molar mass of CaCl_{2}=110.98\frac{g}{mol}

Molar mass of Na_{2}CO_{3}=105.98\frac{g}{mol}

Now with stoichiometry you can find the mass of calcium chloride that reacts with 100mg of soda ash, so:

100mgNa_{2}CO_{3}*\frac{1molNa_{2}CO_{3}}{105.98gNa_{2}CO_{3}}*\frac{1molCaCl_{2}}{1molNa_{2}CO_{3}}*\frac{110.98gCaCl_{2}}{1molCaCl_{2}}=105mgCaCl_{2}

6 0
4 years ago
Let’s define a new language called dog-ish. A word is in the lan- guage dog-ish if the word contains the letters ’d’, ’o’, ’g’ a
attashe74 [19]

Answer and Explanation:

// code

class Main {

   public static void main(String[] args) {

       /*

        *

        *

        * your code

        *

        */

       System.out.println(inDogish("aplderogad"));

       System.out.println(inXish("aplderogad", "dog"));

   }

   // returns true if the word is in dog-ish

   // returns false if word is not in dog-ish

   public static boolean inDogish(String word) {

       // first find d

       if (dogishHelper(word, 'd')) {

           // first find string after d

           String temp = word.substring(word.indexOf("d"));

           // find o

           if (dogishHelper(temp, 'o')) {

               // find string after o

               temp = temp.substring(temp.indexOf("o"));

               // find g

               if (dogishHelper(temp, 'g'))

                   return true;

           }

The output is attached below

       }

       return false;

   }

   // necessary to implement inDogish recursively

   public static boolean dogishHelper(String word, char letter) {

       // end of string

       if (word.length() == 0)

           return false;

       // letter found

       if (word.charAt(0) == letter)

           return true;

       // search in next index

       return dogishHelper(word.substring(1), letter);

   }

   // a generalized version of the inDogish method

   public static boolean inXish(String word, String x) {

       if (x.length() == 0)

           return true;

       if (word.length() == 0)

           return false;

       if (word.charAt(0) == x.charAt(0))

           return inXish(word.substring(1), x.substring(1));

       return inXish(word.substring(1), x.substring(0));

   }

}

PS E:\fixer> java Main true true ne on

PS E:\fixer> java Main true true ne on

5 0
3 years ago
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