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Blababa [14]
3 years ago
9

The application of technology results in human-made things called

Engineering
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

Internet of things

Explanation:

This is a good example where the application of technology results are applied to human made things.

Internet of things (IOT), involves the application of one technology results–the internet, embedded into devices such as refrigerator, television etc so as to send and receive data (digital instructions). Such applications of technology results has revolutionized the way we use "human made things".

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Rotating magnetic field inside a set of conducting wires is a simple description of a what
Advocard [28]

Answer:

hii there

It is called an electromagnet. The strength of the magnetic field produced is determined by the amount of current passing through the conductor. The rotating magnetic field is the rotor and the windings in which current is produced are in the fixed stator.

Explanation:

hope it helps

have a nice day : )

5 0
2 years ago
Inspection with considering a variable uses gages to determine if the product is good or bad. True or False?
irina1246 [14]

Answer:A. 40% B.50% C. 60% Od 70%

Explanation:A. True B. False

4 0
2 years ago
Read 2 more answers
A structural component in the shape of a flat plate 25.0 mm thick is to be fabricated from a metal alloy for which the yield str
balandron [24]

Answer:

The critical length of surface flaw = 6.176 mm

Explanation:

Given data-

Plane strain fracture toughness Kc = 29.6 MPa-m1/2

Yield Strength = 545 MPa

Design stress. =0.3 × yield strength

= 0.3 × 545

= 163.5 MPa

Dimensionless parameter. Y = 1.3

The critical length of surface flaw is given by

= 1/pi.(Plane strain fracture toughness /Dimensionless parameter× Design Stress)^2

Now putting values in above equation we get,

= 1/3.14( 29.6 / 1.3 × 163.5)^2

=6.176 × 10^-3 m

=6.176 mm

5 0
3 years ago
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Oksi-84 [34.3K]
The first one is the answer
8 0
3 years ago
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For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Strike441 [17]

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / 0.02^{0.22

K = 815.8165 Mpa

next, we determine the true strain

(εT) = (σT/ K)^1/n

given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

(εT) = 0.04481 mm

Now, we calculate the instantaneous length

l_i = l_0e^{ET

given that l_0 = 480 mm

we substitute

l_i =480mm × e^{0.04481

l_i =  501.998 mm

Now we find the elongation;

Elongation = l_i - l_0

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

6 0
2 years ago
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