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tekilochka [14]
3 years ago
13

Richard Arkwright is known as father of modern factory system​ why?

Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

He started factories and mills. He created World's first water- powered mill at Cromford, where he employed more than 200 people. This was just the beginning of the many factories which he would later set up. Because of this, Arkwright was known as the father of the modern industrial factory system........Hope you got it

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Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s
Zarrin [17]

Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g)  ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

8 0
3 years ago
Which of the following statements about protons are true?
attashe74 [19]
The second on it true
4 0
3 years ago
Read 2 more answers
Information on caffeine molecules with 3 uses and 3 properties ​
Setler [38]

Answer:

it's uses

1)To improve mental alertness

2) For treating migraine headaches.

3) It increases the blood adrenaline levels

it's properties

1) It is white, odorless and hygroscopic crystalline solid

2) It tastes bitter

3) It is soluble on water

Don't forget to make me brainlist plz

4 0
3 years ago
HELPPPPPPP<br><br> is this chemical or physical reaction
deff fn [24]

Answer:

Chemical reaction

Explanation:

It's creating a whole other substance

7 0
3 years ago
Fill in the missing data point. Show all calculations leading to an answer.
Aleksandr-060686 [28]

Answer:  

1090 mmHg  

Explanation:  

We know that with gases we must use a Kelvin temperatures, so let’s try a plot of pressure against the Kelvin temperature.  

We can create a table as follows  

<u>t/°C</u>  <u>T/K</u>  <u>p/mmHg</u>  

  10   283      726  

  20  293      750  

  40   313      800  

  70  343      880  

100  373       960  

150  423        ???  

I plotted the data and got the graph in the figure below.  

It appears that pressure is a linear function of the Kelvin temperature.  

y = mx + b  

where x is the slope and b is the y-intercept.

===============

<em>Calculate the slope  </em>

I will use the points (275, 700) and (380, 975).  

Slope = Δy/Δx = (y₂ - y₁)/(x₂ -x₁) = (975 -700)/(380 – 275) = 275/105 = 2.619  

So,  

y = 2.619x + b  

===============

<em>Calculate the intercept </em>

When x = 275, y = 700.  

700 = 2.619 × 275 + b  

700 = 720 + b     Subtract 720 from each side and transpose.  

b = -20  

So, the equation of the graph is  

y = 2.619x -20  

===============

<em>Calculate the pressure</em> at 423 K (150°C)  

y = 2.619 × 423 - 20  

y = 1110 - 20  

y = 1090

At 150 °C, the pressure 1090 mmHg.  

The point is approximately at the position of the black dot in the graph.  

7 0
3 years ago
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