Data:
m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (

)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
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Molar Mass

= 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

Solving:



Answer:
By approximation would be letter
D) <span>
337.2 g</span>
Answer:
Solution is 0.28 M
You can also say, [NaCl] = 0.28 mol/L
Explanation:
As you have a solute mass and the solution's volume, you may find the molarity concentration of solution.
Molarity specifies the moles of solute in 1 L of solution
We convert the volume of solution to L → 350 mL . 1L / 1000 mL = 0.350L
We convert the mass of solute to moles → 5.80 g . 1mol / 58.45 g = 0.0992 moles
Molarity (mol/L) = 0.0992 mol /0.350L = 0.28M
C7H16, where C=12.01, and H=1.01, so the weight of the molecule would be 7(12.01)+16(1.01), or 100.23. The percentage of carbon would be found by ((7*12.01)/100.23)*100=83.88% Carbon
((16*1.01)/100.23)*100=16.12% Hydrogen
Friction .......................................................................................
Answer:
I'm sure but send thru this picture for the question so I can help.