Question

A lizard accelerates from 12.0 m/s to 40.0 m/s in 6 seconds. What is the lizard’s average acceleration?

Answer 1

Answer:

4 2/3 m/s

Explanation:

first thing to find the average acceleration is to figure out what the increase in speed was, we can do that by subtracting the original speed from the speed after accelerating, that looks like:

40 - 12 = 28

so the lizard accelerated 28 m/s in 6 seconds, to find the average increase in m/s every second, we divide the m/s by the seconds, which gives us:

28 / 6 = 4.66 = 4 2/3 m/s

Answer 2

Answer:

$\boxed {\boxed {\sf \frac{14}{3} \ or \ 4.6667 \ m/s^2}}$

Explanation:

Acceleration can be found using the following formula.

$a=\frac{v_f-v_1}{t}$

where $v_f$ is the final velocity, $v_i$ is the initial velocity and t is the time.

The lizard started at 12.0 m/s and accelerated up to its final velocity of 40.0 m/s in 6 seconds.

Therefore:

$v_f= 40.0 \ m/s \\v_i= 12.0 \ m/s \\t= 6 \ s$

Substitute the variables into the formula.

$a=\frac{40.0 \ m/s - 12.0 \ m/s}{6 \ s}$

Solve the numerator first and subtract.

• 40.0 m/s - 12.0 m/s= 28 m/s

$a=\frac{ 28 \ m/s}{6 \ s}$

Divide.

$a= \frac{14}{3} \ m/s/s= \frac{14}{3} \ m/s^2$

$a=4.66667 \ m/s^2$

The lizard's average acceleration is 14/3 or 4.66667 m/s²